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anastassius [24]
3 years ago
5

The unit cm3 is used to express

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
3 0
It expresses a cube using cm
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The reaction is called chain reaction when
Maru [420]

Answer:

c. it involves a series of steps, each of which generates a reactive intermediate that brings about the next step

Explanation:

A chain reaction consist of many repeating steps. Chain reaction will never stop until all the reactant has been exhausted. It is more of a cycle of reaction that generate a reactive intermediate that brings about the next step.

Example of a chain reaction is the chlorination of methane.

CH4 + Cl2  ↔ CH3Cl + HCl

CH3Cl  + Cl2  ↔ CH2Cl2 + HCl

CH2Cl2 + Cl2  ↔ CHCl3 + HCl

CHCl3 + Cl2  ↔ CCl4 + HCl

7 0
3 years ago
Explain why heat is often used in a laboratory experiment. a. To warm up the laboratory, b. To speed up a reaction
uysha [10]

Answer:

To speed up a reaction

Explanation:

Heat, as well as catalysts, increase the reaction rate of some chemical reactions since they cause the enzymes or reagents in charge of carrying out the transformation to products to act faster and increase their kinetic energy of reaction.

3 0
3 years ago
Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu
borishaifa [10]

Answer:

\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

                    HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹:       2.7                   0       0

C/mol·L⁻¹:      -x                   +x      +x

E/mol·L⁻¹:   2.7 - x                 x        x

K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}

2. Calculate the pH

\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

     2.7                         x        0.0441

K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}

6 0
3 years ago
1/2 * m * v ^ 2 = mgh
viktelen [127]

C. the square root of 2gh

Explanation:

The square root of 2gh is equivalent to Torricelli's law in the equation.

  given expression:

         \frac{1}{2} m v² = mgh

 to find v, we make it the subject of the expression:

    *multiply both sides of the equation by 2:

             

                     2 x( \frac{1}{2} m v² )= 2 (mgh)

                                      mv²  = 2mgh

    *cancel the mass, m appearing on both sides:

                                    v²  = 2gh

  * find the square root of both side

                                     v = √2gh

Learn more:

Expression brainly.com/question/11207748

#learnwithBrainly

4 0
3 years ago
Lithium nitride reacts with water to produce ammonia and lithium hydroxide according to the equation, Li3N(s) + 3H2O (L) -->
Gemiola [76]

Answer:

0.480 grams

Explanation:

Li₃N(s) + 3D₂O (L) --------------------------> ND₃(g) + 3LiOD (aq)

1             :  3                                            : 1           :  3

Number of moles (n) = Mass in gram/ Molar Mass

Mass of ND₃ = 160 mg

                     = 0.16 g

Molar mass of ND₃=  [14 + (3 x 2.014 )]

                               =    14 + 6.042

                               =  20.042 g/mol

Number of moles of   ND₃  =  0.16/20.042

                                             =  0.007983 moles

From the reaction equation, the mole ratio between   Heavy water (D₂O ) and  ND₃ is  3: 1.

This implies that the number of moles of   Heavy water (D₂O )  required

= 3  x 0.007983 moles

=  0.023949 moles

Molar mass of  Heavy water (D₂O )=  [(2.014 x 2) + 16]

                                                           =  20.028 g/mol

Mass in grams of Heavy water (D₂O )= Number of moles  x Molar mass

                                                            =   0.023949   x  20.028

                                                            =  0.4797 grams

                                                            ≈ 0.480 grams

3 0
3 years ago
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