<span>ppm = mg/L
or
Kg solution
Mass % = Mass of Solute/Mass of solution
0.0390 M = x moles/1L
x = 0.0390 Moles of F-
0.0390 mol x 18.998403 g/mol = 0.7409 g
PPM:
1mg = 1000g
0.7409g = 740.9mg
740.9mg/1L = 740.9mg
Mass Percent:
density 1 g/mL
thus
1 g = 1 mL
thus
1 L = 1 kg
thus
1 L = 1000 g
so,
(0.7409 g/1000 g)*100
= 0.07409% (m/m)</span>
Answer:
shivering is a natural bodily response, the body is trying to heat itself up by moving around.
Answer:
The water will continue to heat up as the experiment progresses.
Explanation:
When a person's fingers are cold or has a muscles ache, one can use chemical hand warmers to heat them up. There are two types of chemical hand warmer products, and they all depend on exothermic chemical reactions to work.
However, ammonium chloride dissolution is endothermic but its crystalization is exothermic. When used as a hand warner with a calorimeter, it is found that the temperature of the water increases steadily due to the crystalization of the ammonium chloride. Hence the answer.
Answer:
0.107 mole of SO2.
Explanation:
1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).
With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.
This can be obtained as follow:
22.4 L contains 1 mole of SO2.
Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.
Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.
<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>
<em>Is questions 1,2,3 right? If not what is the right answers and can someone give me the answer for question 4</em>
<em><u>answer:</u></em><em><u> </u></em>
<em>1</em><em>.</em><em> </em><em>E</em>
<em>2</em><em>.</em><em> </em><em>G</em>
<em>3</em><em>.</em><em> </em><em>Correct </em><em> </em><em>-</em><em> </em><em>F </em>
<em>4</em><em>.</em><em> </em><em>A</em>
<em>5</em><em>.</em><em> </em><em>B</em>
<em>Hope </em><em>this </em><em>helps,</em><em> </em><em>have </em><em>a </em><em>great </em><em>day!</em><em> </em><em>:</em><em>)</em><em> </em>