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3 years ago

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What is the difference between a material having the chemical property of being flammable vs having the chemical property of bei

ng combustible?

1 answer:

makkiz [27]3 years ago

4 0

Answer:

Being flammable means it supports burning,e.g. Oxygen, but being combustible means burning itself too. e.g. Hydrogen.

Explanation:

Hope it helps!!

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I’m learning about heredity

Morgarella [4.7K]

Answer:

1. (See explanation)

2. 46. 23 from the mother’s egg and 23 from the father’s sperm.

Explanation:

ok for number one I am not entirely sure, but I am pretty sure that light, chemicals and temperature can all affect which genes get turned on and off. I am not entirely sure if the question is asking about the environment influencing inherited traits in the form of natural selection tho? If that is something you’re seeing right now, it might be a possible answer. But honestly I am not completely sure.

6 0

3 years ago

Read 2 more answers

Find percent yield:

saveliy_v [14]

<u>Answer:</u> The percent yield of the reaction is 91.8 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For $B_5H_9$ :</u>

Given mass of $B_5H_9$ = 4.0 g

Molar mass of $B_5H_9$ = 63.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol$

<u>For oxygen gas:</u>

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol$

The chemical equation for the reaction of $B_5H_9$ and oxygen gas follows:

$2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O$

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of $B_2H_5$

So, 0.3125 moles of oxygen gas will react with = $\frac{2}{12}\times 0.3125=0.052mol$ of $B_2H_5$

As, given amount of $B_2H_5$ is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of $B_2O_3$

So, 0.3125 moles of oxygen gas will produce = $\frac{5}{12}\times 0.3125=0.130moles$ of water

Now, calculating the mass of $B_2O_3$ from equation 1, we get:

Molar mass of $B_2O_3$ = 69.93 g/mol

Moles of $B_2O_3$ = 0.130 moles

Putting values in equation 1, we get:

$0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g$

To calculate the percentage yield of $B_2O_3$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $B_2O_3$ = 8.32 g

Theoretical yield of $B_2O_3$ = 9.052 g

Putting values in above equation, we get:

$\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%$

Hence, the percent yield of the reaction is 91.8 %

6 0

4 years ago

Complete the sentence indicating the number of protons and electrons in the given ion. Match the numbers in the left column to t

Cloud [144]

Answer: (Chlorine-35)

Element X is Ca

Explanation:

Number of proton plus the number of electron gives the mass number.

5 0

3 years ago

What's the purpose of mitosis and meiosis?

krok68 [10]

The purport of mitosis is cell regeneration, magnification, and asexual reproduction,while the purport of meiosis is the engenderment of gametes for sexual reproduction. Mitosis is a single nuclear division that results in two nuclei that are conventionally partitioned into two incipient daughter cells.

4 0

3 years ago

what is the density of mercury if 205 mL has a mass of 2790 g; round your answer to the nearest 0.1 g/mL

kherson [118]

D = m / V

D = 2790 g / 205 mL

D = 13.60 g/mL

4 0

3 years ago