Answer:
C when lungs expand they fill with air from the atmosphere
Answer:
3 M
Explanation:
Given data
- Moles of sodium hydroxide (solute): 5 moles
- Volume of solution: 2 liters
We can calculate the molar concentration, or molarity (M), of the solution using the following expression.
M = moles of solute / volume of solution (in liters)
M = 5 moles / 2 L
M = 2.5 M ≈ 3 M (if we round off to 1 significant figure)
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Answer:
Ea= -175.45J
A= 3.5×10^14
k=3.64 ×10^14 s^2.
Explanation:
From
ln k= -(Ea/R) (1/T) + ln A
This is similar to the equation of a straight line:
y= mx + c
Where m= -(Ea/R)
c= ln A
y= ln k
a)
Therefore
21.10 3 104= -(Ea/8.314)
Ea=-( 21.10 3 104×8.314)
Ea= -175.45J
b) ln A= 33.5
A= e^33.5
A= 3.5×10^14
c)
k= Ae^-Ea/RT
k= 3.5×10^14 × e^ -(-175.45/8.314×531)
k = 3.64 ×10^14 s^2.
