Answer:
Let the mass of mercury m= 13.6 gm and volume be V=1cm3.
Now change in volume when it is heated upto 50oC,
ΔV=VαΔT
ΔV=1×1.82×10−4×50
ΔV=91×10−4cm3
New volume V1=V+ΔV=1.0091cm3
New density ρ=V1m=1.009113.6=13.48gcm−3
Explanation:
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Answer:
<em>The mass of mercury = 0.136 kg</em>
Explanation:
Density: This is defined as the ratio of mass of a body and the volume of that body. The S.I unit of density is kg/m³. It can be represented mathematically as
D = m/v
m = D× v .......................... Equation 1
Where D = density of the mercury, m = mass of the mercury, v = volume of the mercury.
<em>Given: D = 13600 kg/m², v = 10 cm³ = (10×1/1000000) = 0.00001 m³</em>
<em>Substituting these values into equation 1,</em>
<em>m = 13600×0.00001</em>
<em>m = 0.136 kg.</em>
<em>Therefore the mass of mercury = 0.136 kg</em>
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
42.99°
Explanation:
= Kinetic friction force
= Pulling force at angle
= Weight of the box = 150 N
Kinetic friction force
Pulling force at angle
N = Pulling force
According to question
Applying Newton's second law in the vertical direction we get
The angle is 42.99°
Answer:
If you meant 2.34, 2.34 meters = 23.4 decimeters.
Formula: multiply the value in meters by the conversion factor '10'.
So, 2.34 meters = 2.34 × 10 = 23.4 decimeters.
Hope that helps. x