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nekit [7.7K]
2 years ago
5

A person of weight mg, is standing on a scale in an elevator. What will the

Physics
1 answer:
sergejj [24]2 years ago
8 0

Answer:

B. less than mg

Explanation:

A person's weight changes as he rides an elevator at a constant velocity. If the elevator is moving downward,<u> the person's weight becomes lesser.</u> He is considered to be in "free fall" due to <em>gravity.</em> However, the opposite happens when the elevator goes upward. The person will feel heavier because he is going against gravity. This means his weight is more than his actual weight. If the person will stand on an elevator that doesn't move, his weight will just be the same. All of these is due to <em>Newton's Second Law of Motion</em> where an object's acceleration relies on its <em>force</em> and<em> mass.</em>

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mamaluj [8]

ANSWER:

(a) 1036 N

(b) -1036 N

(c) 2590 N

STEP-BY-STEP EXPLANATION:

Given:

Mc = 1400 kg

Mt = 560 kg

a = 1.85 m/s^2

(a)

Force by car on trailer:

\begin{gathered} F_c=m\cdot a \\ F_c=560\cdot1.85 \\ F_c=1036\text{ N} \end{gathered}

(b)

\begin{gathered} F_t=-F_c \\ F_t=-1036\text{ N} \end{gathered}

(c)

\begin{gathered} F_n=1400\cdot1.85 \\ F_n=2590\text{ N} \end{gathered}

3 0
10 months ago
What is the Ozone layer?
yaroslaw [1]
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4 0
2 years ago
Read 2 more answers
Which of the following are true for acceleration?
Fittoniya [83]

The SI unit for acceleration is m/s2 ( D)

6 0
2 years ago
If the moon were twice as far from years as it is now the following would be true
zubka84 [21]
The question is incomplete.

The distance between the Moon and Earth influences: 1) the attractive gravitational force between them, 2) the tides, 3) the eclipses, 4) the period of each full turn of the moon around the Earth.

Assuming the question refers to the gravitational attraction, we must use the fact that, as per, Newton's Universal Gravitaional Law, the attractive force between the two bodies is inversely related to the square distance that separates them.

Then, if the Moon were twice as far, the gravitational pull would be one fourth (1/4) of actual pull.

7 0
3 years ago
A racecar driver steps on the gas, and his racecar travels 20 meters in 2 seconds starting from rest. The acceleration of the ra
givi [52]

Answer:

2.5m/s^2

Explanation:

Step one:

given

distance = 20meters

time = 2 seconds

initial velocity u= 0m/s

let us solve for the final velocity

velocity = distance/time

velocity= 20/2

velocity= 10m/s

v^2=u^2+2as\\\\10^2=0^2+2*a*20\\\\100=40a

divide both sides by 40

a= 100/40\\\\a=10/4\\\\a= 5/2\\\\a= 2.5m/s^2

5 0
3 years ago
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