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nekit [7.7K]
3 years ago
5

A person of weight mg, is standing on a scale in an elevator. What will the

Physics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

B. less than mg

Explanation:

A person's weight changes as he rides an elevator at a constant velocity. If the elevator is moving downward,<u> the person's weight becomes lesser.</u> He is considered to be in "free fall" due to <em>gravity.</em> However, the opposite happens when the elevator goes upward. The person will feel heavier because he is going against gravity. This means his weight is more than his actual weight. If the person will stand on an elevator that doesn't move, his weight will just be the same. All of these is due to <em>Newton's Second Law of Motion</em> where an object's acceleration relies on its <em>force</em> and<em> mass.</em>

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C I think not totally sure
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Giving quadrilateral a(2,-1 ) b ( 1,3) c(6,5) d(7,1) you want to prove that it is a parallelogram by showing opposite sides are
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Answer:

Opposite sides are congruent (AB = DC).

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What is the frequency of an x- ray if the wavelength is 4.5 E - 10m?
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3 years ago
When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g
olya-2409 [2.1K]

Answer:

v1=21.81m/s

Explanation:

<em>When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 44 m/s. Neglect the mass of the club handle and determine the speed (in m/s) of the golf ball just after impact.</em>

According to the law of conservation of momentum, if the net external force on a system is zero, then the linear momentum of the system is conserved.

During collision of two particles, the external force on the system of two colliding particles is zero (only internal force acts between the colliding particles), therefore, the momentum is conserved during the collision.

Answer and Explanation:

Given :

head of the golf club=160g

velocity of the golf club=50 m/s

golf ball mass=46g

velocity=om/s

m1u1+m2u2=m1v1+m2v2.........................................1

160*50 +46*0=160*44+46*v1

8000=7040+46v1

960=46v1

v1=960/46

v1=21.81m/s

3 0
3 years ago
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