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DerKrebs [107]
2 years ago
8

Perform the indicated operation 10ab/c^3d ÷ 15ab^3/7c^3d^4​

Mathematics
1 answer:
andrew11 [14]2 years ago
6 0

Step-by-step explanation:

=  \frac{10ab}{ {c}^{3}d }  \div  \frac{15a {b}^{3} }{7 {c}^{3}  {d}^{4} }

=  \frac{10ab}{ {c}^{3} d}  \times  \frac{7 {c}^{3} {d}^{4}  }{15a {b}^{3} }

=  \frac{70ab {c}^{3} {d}^{4}  }{15a {b}^{3}  {c}^{3} d}

=  \frac{70}{15}  {a}^{1 - 1}  {b}^{1 - 3}  {c}^{3 - 3}  {d}^{4 - 1}

=  \frac{14}{3}  {a}^{0}  {b}^{ - 2}  {c}^{0}  {d}^{3}

=  \frac{14 {d}^{3} }{3 {b}^{2} }

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Answer:

see explanation

Step-by-step explanation:

To solve the given quadratic equations, equate to zero, factorise and solve

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given

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3 years ago
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dsp73

Answer:

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Step-by-step explanation:

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lina2011 [118]

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6 0
2 years ago
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Find the measure of ZDCF. C F mDF = 49 G E MEG = 127 Find the measure of angle DCF​
AleksandrR [38]

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

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Solution

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Answer:

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Step-by-step explanation:

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