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DerKrebs [107]
2 years ago
8

Perform the indicated operation 10ab/c^3d ÷ 15ab^3/7c^3d^4​

Mathematics
1 answer:
andrew11 [14]2 years ago
6 0

Step-by-step explanation:

=  \frac{10ab}{ {c}^{3}d }  \div  \frac{15a {b}^{3} }{7 {c}^{3}  {d}^{4} }

=  \frac{10ab}{ {c}^{3} d}  \times  \frac{7 {c}^{3} {d}^{4}  }{15a {b}^{3} }

=  \frac{70ab {c}^{3} {d}^{4}  }{15a {b}^{3}  {c}^{3} d}

=  \frac{70}{15}  {a}^{1 - 1}  {b}^{1 - 3}  {c}^{3 - 3}  {d}^{4 - 1}

=  \frac{14}{3}  {a}^{0}  {b}^{ - 2}  {c}^{0}  {d}^{3}

=  \frac{14 {d}^{3} }{3 {b}^{2} }

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Answer:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

Step-by-step explanation:

To find all pairs of natural numbers which are solution to a+b=42, we need to first choose a value to one of them (let's choose 'a'), and that value will be the lowest possible, so we begin with a=1, and then we increase to 2, and 3, and so on.

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