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Butoxors [25]
3 years ago
6

A LASIK vision-correction system uses a laser that emits 10-ns-long pulses of light, each with 3.0 mJ of energy. The laser beam

is focused to a 0.80-mm-diameter circle on the corneaWhat is the electric field amplitude of the light wave at the cornea?.
Physics
1 answer:
lyudmila [28]3 years ago
7 0
 <span>P = energy/t = 0.0025/1E-8 = 250000 W 
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2 
I(peak) = 2I(ave) = 8.8113463E11 W/m^2 
Electric field E = sqrt(I(peak)*Z0) = 1.8219499E7 V/m, where 
free-space impedance Z0 = sqrt(µ0/e0) = 376.73031 ohms</span>
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forsale [732]

Answer:

Is there a question?

Explanation:

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3 years ago
An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 V for 0.65 ms. The resistance of t
9966 [12]

Answer: a) 0.11 Amp b) 0.000429 Joules c) 0.000514 watt

Explanation:

a)current

I=V/r I=6.0/550 =1.1*10^-2 A

b) energy

E= 1.1*10^-2 x (6.0) x 0.00065s(<-- remember to convert ms to seconds) = 0.000429J

C) Average power

P = (0.000429 x 72) / 60

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3 years ago
If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?
Arada [10]

The force on the fry is 0.015 N

Explanation:

We can find the force acting on the fry by using Newton's second law:

F=ma

where

F is the net force on the fry

m is its mass

a is its acceleration

For the fry in this problem,

m=3 g = 0.003 kg

a=5.0 m/s^2

Therefore, the force exerted on the fry is

F=(0.003)(5)=0.015 N

Learn more about Newton's second law here:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?
vladimir1956 [14]

Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s

So, their average velocity is 1.6 m/s.

5 0
4 years ago
Physics question 28 plz help me
Alexus [3.1K]

Answer:

a. I = 30 A

b. E = 1080000 J = 1080 KJ

c. ΔT = 12.86°C

d. Cost = $ 4.32  

Explanation:

a.

The current in the coil is given by Ohm's Law:

V = IR\\I = \frac{V}{R}

where,

I = current = ?

V = Voltage = 120 V

R = Resistance = 4 Ω

Therefore,

I = \frac{120\ V}{4 \Omega}\\

<u>I = 30 A</u>

<u></u>

b.

The energy can be calculated as:

E = VIt\\E = (120\ V)(30\ A)(5\ min)(\frac{60\ s}{1\ min})\\

<u>E = 1080000 J = 1080 KJ</u>

<u></u>

c.

For the increase in the temperature of water:

E = mC\Delta T\\

where,

m = mass of water = 20 kg

C = specific heat of water = 4.2 KJ/kg.°C

Therefore,

1080\ KJ = (20\ kg)(4.2\ KJ/kg.^oC)\Delta T

<u>ΔT = 12.86°C</u>

<u></u>

d.

First, we will calculate the total energy consumed:

E=(Power)(Time)\\E=VI(Time)\\E = (120\ V)(30\ A)(0.5\ h/d)(30\ d)\\E = 54000\ Wh\\E = 54 KWh

Now, for the cost:

Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(54\ KWh)

<u>Cost = $ 4.32</u>

7 0
3 years ago
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