I am pretty sure it is C.
Answer:
lubricant (decrease friction).
control production speed.
use only when required.
Answer:
Newton gives us force
F=-G*M*m/R^2
Divide by the mass of the object to get acceleration
a=F/m = GM/R^2
You are solving the distance where the force from the moon equals the force from the Earth -
a= G*(mass of earth)/R^2 - G*(mass of moon)/(384400000-R)^2=0
Or in other words
G*(mass of earth)/R^2=G*(mass of moon)/(384400000-R)^2
Divide by G*(mass of the moon) and multiply by R^2 to get terms on both sides
G*(mass of earth)/(G*(mass of moon))=R^2/(384400000-R)^2
Since the mass of the moon and earth are fixed, the left side is a number
81.3 = R^2/(384400000-R)^2 → R^2/(384400000-R)^2–81.3 = 0
simplify
R/(384400000-R) = 9.01665
R=346024000 = 346,024 km.
Explanation:
The car would go from zero to 58.0 mph in 2.6 sec.
Since the force on the car is constant, therefore the acceleration of the car would also be constant.
Now for constant acceleration we can use the equation of motion
Using first equation of motion to calculate the acceleration of the car
v=u+at
29=0+a×1.30 ...... Eq. (1)
Again using the first equation of motion
58=0+a*t ....... Eq. (2)
Dividing eq. (2) with equation 1
t=2×1.3
t=2.6 sec