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3 years ago

10

A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha

t value of θ will give the maximum horizontal range?

1 answer:

Irina-Kira [14]3 years ago

6 0

Answer:

pahingi po ng pic pls para masagutang kopo iyan

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5 ohm resistor is in series with a bulb, a switch and a 12V battery.

Nikitich [7]

Answer: yo light bill finna be turnt off im just kidding 1`

Explanation:

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4 years ago

What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 4.50 w/m2 ?

Oksi-84 [34.3K]

Average intensity of electromagnetic wave is given by

I= (speed of light*permittivity*sq. electric field)/2

Speed of light = 3x10^8 m/s
Permittivity = 8.85x10^-12

Therefore,
Electric field = sqrt (2I/ (speed of light xpermittivity)) = sqrt ((2*4.50)/(3*10^8*8.85*10^-12)) = 58.22 V/m

7 0

3 years ago

A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i

victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

$F= \frac{kqQ}{r^2}$

Where,

$k = 8.99 * 10^9 N m^2 / C^2.$

q = charges of the objects

r= distance/radius

Our values are previously given, so

$q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59$

Replacing,

$F=\frac{kqQ}{r^2}$

$F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}$

$F= 4.8423N$

The force acting on the block are given by,

$F-mgsin\theta = ma$

$a = \frac{F-mgsin\theta}{m}$

$a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}$ $a = 10.31m/s^2$

Therefore the box is accelerated upward.

3 0

3 years ago

Which of the following characteristics of the earth are essential to the existence of life?

Rudiy27

Answer: What makes the Earth habitable? It is the right distance from the Sun, it is protected from harmful solar radiation by its magnetic field, it is kept warm by an insulating atmosphere, and it has the right chemical ingredients for life, including water and carbon.

Explanation:

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3 years ago

3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the

andreev551 [17]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

5 0

3 years ago