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Olin [163]
3 years ago
6

Identify the energy transformations in the image below:

Physics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

B

Explanation:

Electrical to Radiant.

I think

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Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m /
castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

d is the distance covered.

t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

6 0
2 years ago
Which statement is the best interpretation of the ray diagram shown?
Stells [14]

Answer: a convex lens forms a larger virtual image

Explanation: i just took the quiz

3 0
3 years ago
Read 2 more answers
Birdman is flying horizontally at a
den301095 [7]

Answer:

68 m

Explanation:

Given that the horizontal velocity of the birdman = 17 m/s and

the height, h= 78 m.

The gravitational force is acting in the downward direction, so it will not change the horizontal speed.

The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.

Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, u_0=17 m/s.

In the vertical direction, u = 0,

The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e

s= 78 m

Let t be the time taken to cover a distance of 78 m.

Now, applying the equation of motion in the vertical direction,

s=ut+\frac 12 at^2

where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.

Here, a=g=9.81 m/s^2, so

78=0\times t +\frac 12 (9.81)t^2

\Rightarrow t^2=(78\times2)/9.81

\Rightarrow t = 4 seconds.

Hence, the time taken to reach the ground is 4 seconds.

As the horizontal speed, u_0=17 m/s, is constant throughout the journey, so

the horizontal distance covered by turd

= u\times t

= 17 \times 4 = 68 m.

So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly  above the start of the field.

Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.

5 0
3 years ago
Scientists have discovered just over _____ different elements with unique properties.
Y_Kistochka [10]
100. (: hope this helps
8 0
3 years ago
Read 2 more answers
What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?
erica [24]
We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s

Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules

In short, Your Final answer would be 2.093 × 10⁻²¹ J

Hope this helps!
5 0
3 years ago
Read 2 more answers
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