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Ipatiy [6.2K]
3 years ago
5

Please help meeeeeeeeee

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0

Step-by-step explanation:

1. 10-(2+3) = 5

2. 2x3 - 10 = -4

3. 3 x (4-2) = 6

4. (3+5) / 4 = 2

5. (5-2) x 3 = 9

6. (9-4) + 5 = 10

Lerok [7]3 years ago
5 0
1) 10 - (2+3) = 5

2) 10 - (2x3) = 4

3) 3 x (4-2) = 6

4) (3+5) / 4 = 2

5) (5-2) x 3 = 9

6) 5 + (9-4) = 10
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5x-3y=-11<br> x-2y=2<br> this is for home work please help
ale4655 [162]
5x - 3y = 11 ⇒ 5x - 3y = 11  ⇒   5x - 3y = 11
  x - 2y = 2   ⇒ -5(x - 3y) = 2 ⇒ <u>-5x + 15y = 2</u>
                                                           <u>12y</u> = <u>13</u>
                                                            12     12
                                                             y = 1 1/12
                                                 5x - 3(1 1/12) = 11
                                                 5x - 3 1/4 = 11
                                                <u>      +3 1/4    +3 1/4</u>
                                                            <u> 5x</u> = <u>14 1/4</u>
                                                              5          5
                                                               x = 2 17/20
                                                 (x, y) = (2 17/20, 1 1/12)
8 0
3 years ago
Which rules has a scale factor of 5 and shifted up and to the left?
serious [3.7K]

Answer:

185 37 = 5 1; the scale factor is 5: 1. So every other linear measure is multiplied times 5. If we have the big right triangle and want to scale it down to make the smaller one, we write this: 37 185 = 1 5

Step-by-step explanation:

4 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
3 years ago
The square of a number, x, is 16 less than eight times the number. What is the number? Type the correct answer in the box. Use n
liraira [26]

Given :

The square of a number, x, is 16 less than eight times the number.

To Find :

The value of x .

Solution :

The mathematical equation with all given data is :

x^2=8x-16\\\\x^2-8x+16=0\\\\x^2-4x-4x+16=0\\\\x(x-4)-4(x-4)=0\\\\(x-4)^2=0\\\\x=4

Therefore , the value of x is 4 .

Hence , this is the required solution .

3 0
3 years ago
What is the vertex of<br> f(x) = (x - 7)?
valina [46]
Answer: This equation does not have a vertex.

If the equation is not curved or composed of two straight lines it does not have a vertex.

If you need further explanation let me know. :)
3 0
3 years ago
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