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Ipatiy [6.2K]
2 years ago
5

Please help meeeeeeeeee

Mathematics
2 answers:
rosijanka [135]2 years ago
7 0

Step-by-step explanation:

1. 10-(2+3) = 5

2. 2x3 - 10 = -4

3. 3 x (4-2) = 6

4. (3+5) / 4 = 2

5. (5-2) x 3 = 9

6. (9-4) + 5 = 10

Lerok [7]2 years ago
5 0
1) 10 - (2+3) = 5

2) 10 - (2x3) = 4

3) 3 x (4-2) = 6

4) (3+5) / 4 = 2

5) (5-2) x 3 = 9

6) 5 + (9-4) = 10
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Solve the following system of equations graphically. x + y - 4 = 0 x - y = 0 The solution lies in quadrant _____. A.I B.II C.III
marin [14]
Quadrant 1 should be your answer
3 0
3 years ago
Anita brings 6 dolls to her grandma's house. These dolls represents 20% of Anita doll collection,as shown in the diagram.
8090 [49]

20/100 =x/6  

20 multiply 6 =120

120 divide by 100 =1.2

6 0
3 years ago
Factorize (2u+3u)(u+v)-2u+3v​
Stolb23 [73]

Answer:

Step-by-step explanation:

(2u+3u)(u+v)-2u+3v

=2u(u+v)+3u(u+v)-2u+3v

=2u^2+2uv+3u^2+3uv-2u+3v

=5u^2+5uv-2u+3v

7 0
2 years ago
Bob discovers a box with 30 identical, used, rechargeable batteries in his attic.
monitta

Answer:

a) All of them are out of charge = 9.31x10⁻¹⁰

b) 20% of them are out of charge = 5.529x10⁻⁴

Step-by-step explanation:

This problem can be modeled as a binomial distribution since

There are n repeated trials and all of them are independent of each other.

There are only two possibilities: battery is out of charge and battery is not out of charge.

The probability of success does not change with trial to trial.

Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50

P = 0.50

1 - P = 0.50

a) All of them are out of charge?

Probability = nCx * P^x * (1 - P)^n-x

Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰

Probability = 9.31x10⁻¹⁰

b) 20% of them are out of charge?

0.20*30 = 6 batteries are out of charge

Probability =₃₀C₆(0.50)²⁴(0.50)⁶

Probability = 5.529x10⁻⁴

5 0
3 years ago
Segment AB has endpoints on the coordinate grid where A is (- 18, 5) and B is (- 4, 5) Point Z is located exactly 1/8 of the dis
fenix001 [56]

Given:

Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).

Point Z is located exactly 1/8 of the distance from A to B.

To find:

The value of the x-coordinate of point Z.

Solution:

Point Z is located exactly 1/8 of the distance from A to B.

AZ:AB=1:8

AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7

It means point Z divided segment AB in 1:7.

Using section formula, the x coordinate of point Z is

x-coordinate=\dfrac{mx_2+nx_1}{m+n}

x-coordinate=\dfrac{1(-4)+7(-18)}{1+7}

x-coordinate=\dfrac{-4-126}{8}

x-coordinate=\dfrac{-130}{8}

x-coordinate=-16.25

Therefore, the required x-coordinate of point Z is -16.25.

3 0
3 years ago
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