Answer:
- The first picture attached is the diagram that accompanies the question.
- The<u> second picture attached</u> is the diagram with the answer.
Explanation:
In the box on the left there are 8 Cl⁻ ions and 8 Na⁺ ions.
The dissociaton equation for NaCl(aq) is:
- NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)
The dissociation equation for CaCl₂ (aq) is:
- CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)
A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.
Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half) and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).
Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.
<span>5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid.
For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved.
Atomic weight of Sodium = 22.989769
Atomic weight of Sulfur = 32.065
Atomic weight of Carbon = 12.0107
Atomic weight of Oxygen = 15.999
Atomic weight of Hydrogen = 1.00794
Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol
Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999
= 105.987238 g/mol
The balanced equation for the reaction of Na2CO3 with H2SO4 is
Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O
so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So
105.987238 g/mol / 98.07688 g/mol = 1.080655
So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication.
5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg.
Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg</span>
It represents the boundary between what is considered to be ionic or a covalent bond.
Explanation:
Expression for the coefficient of thermal expansion is as follows.
where, V = initial volume
= Final volume - initial volume
= (712.6 - 873.6) 
= -161
Now, we will calculate the change in temperature as follows.
= Final temperature - Initial temperature
= (10 + 273) K - (70 + 273) K
= 283 K - 343 K
= -60 K
Substituting these values into the equation as follows.
= 0.00307 
It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.
