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m_a_m_a [10]
3 years ago
12

-x times -x what is the answer​

Physics
2 answers:
Brilliant_brown [7]3 years ago
5 0

Answer:

Explanation:

x

Vinil7 [7]3 years ago
3 0

Answer:

a negative times a negative is a positive so the answer is just x

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. The penalties for a person's second DUI conviction include completion of __________ hours of DUI school.
Kobotan [32]
<span>The penalties for a person's second DUI conviction include completion of </span>21 hours of DUI school.


4 0
3 years ago
car rides on four wheels that are connected to the body of the car by spring assemblies that let the wheels move up and down ove
Tomtit [17]

Answer:

78.4 KN/m

Explanation:

Given

mass of person 'm' =80 kg

car dips about i.e spring stretched 'x'=   1 cm  => 0.01m

acceleration due to gravity 'g'= 9.8 m/s^2

as we know that,in order to find approximate spring constant we use Hooke's Law i.e  F=kx

where,

F = the force needed

x= distance the spring is stretched or compressed beyond its natural length

k= constant of proportionality called the spring constant.

F=kx ---> (since f=mg)

mg=kx

k=(mg)/x

k=(80 x 9.8)/ 0.01

k=78.4x10^3

k=78.4 KN/m

3 0
3 years ago
Read 2 more answers
Who can do my worksheet for me
timurjin [86]

Answer:

what  is it on? like name one of the questions

Explanation:

5 0
3 years ago
The heat capacity of object B is twice that of object A. Initially A is at 300 K and B at 450 K. They are placed in thermal cont
ivann1987 [24]

Answer:

The final temperature of both objects is 400 K

Explanation:

The quantity of heat transferred per unit mass is given by;

Q = cΔT

where;

c is the specific heat capacity

ΔT is the change in temperature

The heat transferred by the  object A per unit mass is given by;

Q(A) = caΔT

where;

ca is the specific heat capacity of object A

The heat transferred by the  object B per unit mass is given by;

Q(B) = cbΔT

where;

cb is the specific heat capacity of object B

The heat lost by object B is equal to heat gained by object A

Q(A) = -Q(B)

But heat capacity of object B is twice that of object A

The final temperature of the two objects is given by

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}

But heat capacity of object B is twice that of object A

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K

Therefore, the final temperature of both objects is 400 K.

4 0
3 years ago
You are given an unknown solid substance of mass 500 g and you want to estimate its specific heat. unfortunately, you don’t have
Julli [10]

Answer:

Option C) 2,090 J/(mol K)

Explanation:

Data:

Volume in the beaker = 429 ml

temperature  = 20° C

Density = 789 kg/m³

Equilibrium reading = 429

volume change = 29 ml

                          = 0.029 L

Energy change = mcΔT

                       U + PΔV

7 0
3 years ago
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