Answer:
balanced equation mole ratio 5 2 mol NO/1 mol O2
10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2
20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO
actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2
Because the actual mole ratio of NO:O2 is larger than the balanced equation mole
ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.
Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO
0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO
Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2
Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N
Explanation:
Yes, IF entropy is high enough
Simple sugar! Good luck! :)
Answer:
<h3>OF2 Molecular Geometry</h3><h3 /><h3>As only atoms are bonded with the central atom, it has a molecular geometry similar to AX2 that corresponds to linear geometry. Although the electron geometry of OF2 is tetrahedral, its molecular geometry is linear.</h3>
Explanation:
Hope it helps
<em>#</em><em>C</em><em>a</em><em>r</em><em>r</em><em>y</em><em>O</em><em>n</em><em>L</em><em>e</em><em>a</em><em>r</em><em>n</em><em>i</em><em>n</em><em>g</em>
