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MatroZZZ [7]
3 years ago
5

Determine the number of hydrogen atoms in the following compound 3Cu(C2H3O2)2

Chemistry
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:5

Explanation:(H3) is 3 (H3)2 is 5

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5 witch of these is a covalent compound? NO2 B LiCL C AICI3 D Na2S
arlik [135]
NO2 is a covalent compound
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4 years ago
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What is the chemical formula for iron(II) hydroxide?<br> Fe, OH<br> Fe(OH)<br> FeOH<br> 0 FeOH
denpristay [2]
None of the above, it is Fe(OH)2
3 0
3 years ago
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A 2.026g sample of a hydrate of sodium carbonate (Na2CO3) is heated to remove water. After heating, the mass of the sample is 0.
OLEGan [10]

Answer:

62.98 % of the sample of hydrate is water

Explanation:

Step 1: Data given

Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams

After heating, the mass of the sample is 0.750 g

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mass of water

Mass water = mass of hydrate - mass of sample after heating

Mass water = 2.026 grams - 0.750 grams

Mass water = 1.276 grams

Step 3: Calculate mass % percent of water

Mass % of water = (mass of water / total mass hydrate) * 100 %

Mass % of water = (1.276 grams / 2.026 grams) *100 %

Mass % of water = 62.98 %

62.98 % of the sample of hydrate is water

7 0
3 years ago
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How many grams are in 4.23 x 1024 atoms of He?
Dmitry [639]

Answer:

28.11g

Explanation:

Step 1:

Background understanding:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This also indicates that 1 mole of helium (He) contains 6.02x10^23 atoms.

1 mole of He = 4g

Step 2:

Determination of the mass of He that contain 4.23x10^24 atoms. This is illustrated below:

4g of He contains 6.02x10^23 atoms.

Therefore Xg of He will contain 4.23x10^24 atoms i.e

Xg of He = (4x4.23x10^24)/6.02x10^23

Xg of He = 28.11g

Therefore, 28.11g of He contains 4.23x10^24 atoms

7 0
3 years ago
At a particular pressure and temperature, nitrogen gas effuses at the rate of 79 mL/s. Under the same conditions, at what rate w
amm1812

Rate of Sulfur dioxide : 2730.44 mL/s

<h3>Further explanation  </h3>

Graham's law: <em>the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  </em>

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

MW of N₂ = 28 g/mol

MW SO₂ = 64 g/mol

\tt 28\times 79^2=64\times r_2^2\\\\r_2^2=\dfrac{28\times 79^2}{64}=2730.44~mL/s

3 0
3 years ago
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