Answer:
0.028kg
Explanation:
We were given 2.6 × 1023 molecules of SO 2 That means that
N = 2.6 × 1023 molecules
Use
n (number of moles) = N
NA (Avogadro's constant)
to get
n =2.6×1023 molecules
6.02 ×1023 molecules/mol = 0.432 moles
Now use
m = n × M (molar mass)
to get
m = 0.432 mol × 64.066 g/mol = 27.677 g
So
m (in kilograms) = 27.677 g
103 g/kg = 0.028 kg
Answer:
The number and the kinds of atoms in the compound
Explanation:
- A chemical formula of a compound contains symbols o the atoms of the elements present in the compound as well as the number of atoms of each element in the form of subscripts.
- Therefore it helps us to know the elements in a compound and the number of atoms in the compounds.
Answer:
Atomic Oribal
Explanation:
There are four basic types of electron orbitals – s, p, d, and f. (Visual representations can be found in the tutorial above.) The s subshell is a spherical orbital which can contain up to two electrons. Each energy level has one s subshell.
Answer:
pH of the buffer is 10.10
Explanation:
trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.
To determine the pH of the buffer we use H-H equation for weak bases:
pOH = pKb + log [Conjugate acid] / [Weak base]
<em>pKb is -log Kb = 4.20</em>
<em />
pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]
Replacing the concentrations of the problem:
pOH = 4.20 + log [0.20M] / [0.40M]
pOH = 3.90
As pH = 14 -pOH
<h3>pH of the buffer is 10.10</h3>
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