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Andreas93 [3]
2 years ago
8

Vanadium (III) hydroxide reacts with hydrobromic acid according to the following balanced chemical equation: V(OH)3 (s) + 3 HBr

(aq) + 3 H20 (1) + VBra (s) If 11.0 mol of V(OH)3 reacts with 21.0 mol of HBr, then which substance is the excess reagent in the above reaction?​
Chemistry
1 answer:
9966 [12]2 years ago
3 0

Answer:

TY and I like the country studies.

Explanation:

ok bye por a mathmu n bye for now and hope you have patience.

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Complete the statement<br>qxy- bxy+cxy= xy( )​
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In a liquid, the energy required to increase the surface of the area by a unit amount is called :a.dipole-dipole force. b.viscos
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Answer:

D. Surface tension.

Explanation:

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5 0
3 years ago
Determine the bonding type for boron trihydride given the electronegativity on the Pauling scale for boron is 2.0 and for hydrog
Anika [276]

Answer: The bond between boron and hydrogen in boron trihydride is covalent bond.

Explanation:

The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms. According to the pauling's electronegativity rule:

  • If \Delta \chi=0, then the bond is non-polar.
  • If \Delta \chi\leq 1.7, then the bond will be covalent.
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We are given:

Electronegativity for boron = 2.0

Electronegativity for hydrogen = 2.1

\Delta \chi=\chi_{H}-\chi_{B}\\\\\Delta \chi=2.1-2.0=0.1

As, \Delta \chi is less than 1.7 and not equal to 0. Hence, the bond between boron and hydrogen is covalent bond.

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