1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alina1380 [7]
3 years ago
8

Complete the statementqxy- bxy+cxy= xy( )​

Chemistry
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

xy (-b+c+q) is the answer to this

You might be interested in
How might two lithospheric plates interact with each other?
Natalija [7]

Answer:

Ur answer is B. I, II, and III

Explanation:

Tectonic plates can interact with each other.

7 0
2 years ago
Read 2 more answers
Use the following equation to answer the questions below:
Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

3 0
3 years ago
Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe? auau cucu mnmn agag
Cerrena [4.2K]

Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.

Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.

Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Learn more about electrode here:

brainly.com/question/17060277

#SPJ4

3 0
2 years ago
Find the vapor pressure of a water solution in which the
zheka24 [161]

Answer:

The vapor pressure in solution is 0,0051 atm

Explanation:

This is the formula for vapor pressure lowering, the colligative property.

P vapor = Pressure sv pure . Xsv

Where Xsv is data.

Xsv means Molar fraction (moles solvent/total n° moles)

Vapor pressure of water, pure is 17.5 mmHg

P vapor = 0,0313 atm . 0163

P vapor in solution = 0,0051 atm

Molar fraction does not have units

A solution will have less vapor pressure than that observed in the pure solvent.

5 0
3 years ago
Metals can be highly purified using electrolysis. Which equation best reflects the overall process of purifying copper?
makvit [3.9K]

Answer:

A. Cu^+2(aq)cathode ---> Cu^+2(aq)anode

Explanation:

Electrolysis is the process in which current is passed through a solution thereby causing a chemical change at the anode and cathode. Copper is being purified using electrolysis by using impure copper at the anode and pure copper at the cathode. This pure and impure copper are placed in a copper(ii)sulfate electrolyte solution and dc current is made to pass through it.  The resulting changes at the anode and cathode are given by the equation:

cathode: Cu²⁺  + 2e⁻    ⇒     Cu

anode:    Cu     ⇒       Cu²⁺  + 2e⁻

3 0
3 years ago
Read 2 more answers
Other questions:
  • The humidity levels inside the greenhouse.
    15·1 answer
  • What happens when you add or change a subscript
    8·1 answer
  • Electrons in the first energy level of an atom
    10·1 answer
  • Find the element that has the same chemical properties as magnesium,but fewer protons
    12·1 answer
  • 1. State how increasing the temperature of a gas changes its volume, assuming pressure is held
    10·1 answer
  • Which of the following statements is true?
    10·1 answer
  • In which state of matter are particles packed tightly together in fixed positions?
    11·1 answer
  • ____________ rays show areas where large quantities of energy are released.
    5·1 answer
  • Example of each class of polydentate ligands
    14·1 answer
  • These graphs compare the people who oppose the use of nuclear energy to the people
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!