Answer:
- <u>77.8 m/s, downward</u>
Explanation:
For uniform acceleration motion, the average speed is equal to half the soum of the initial velocity, Vi, and the final velocity, Vf
- Average speed = (Vf + Vi)/2
Also, by definition, the average speed is the distance divided by the time:
- Average speed = distance / time
Then:
Other kinematic equation for uniform acceleration is:
Since the window is falling and the air resistance is ignored, a = g (gravitational acceleration ≈ 9.8m/s²)
Replacing the known values we can set a system of two equations:
From (Vf + Vi)/2 = 300m/6.62s
(Vf + Vi) = 2 × 300m/6.62s
- Vf + Vi = 90.634 equation 1
From Vf = Vi + a×t
Vf - Vi = 9.8 (6.62)
- Vf - Vi = 64.876 equation 2
Adding the two equations:
- Vf = 77.8 m/s downward (velocities must be reported with their directions)
Answer:The net force on the block is zero.
Explanation:
Given
Block is being pulled upward along an inclined surface at a constant speed
As speed is constant and moved in a straight line along the plane therefore its velocity is also constant .
and change in velocity is equal to acceleration therefore acceleration is zero here i.e. net force is zero acting on the body.
Answer:
I think the answer is A
Explanation:
I need this brainliest answer please
Answer:
Final velocity (v) = 36 m/s
Distance traveled (s) = 2,160 m
Explanation:
Given:
Initial velocity (u) = 0
Acceleration (a) = 0.3 m/s
Time travel (t) = 2 minutes = 120 seconds
Find:
Final velocity (v) = ?
Distance traveled (s) = ?
Computation:
v = u + at
v = 0 + 0.3(120)
v = 0.3(120)
v = 36 m/s
Final velocity (v) = 36 m/s
Distance traveled (s) = ut + (1/2)at²
Distance traveled (s) = (0.5)(0.3 × 120 × 120)
Distance traveled (s) = 2,160 m
