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Contact [7]
3 years ago
10

Which type of radio broadcast has a greater broadcast range am or fm

Physics
1 answer:
Finger [1]3 years ago
3 0
The answer is FM...That's why all the good stations that people listen to are on FM
You might be interested in
Explain how the pressure at the bottom of a container depends on the container shape and the fluid height
3241004551 [841]

The pressure at the bottom of a column of fluid in a container
depends only on the depth of the fluid, not on the shape of the
container.  The pressure is simply the result of the weight of the
fluid resting on the bottom.

3 0
3 years ago
A projectile is launched from ground level with an initial speed of 47 m/s at an angle of 0.6 radians above the horizontal. It s
Zarrin [17]

Answer:

30.67m

Explanation:

Using one of the equations of motion as follows, we can describe the path of the projectile in its horizontal or vertical displacement;

s = ut ± \frac{1}{2} at^2               ------------(i)

Where;

s = horizontal/vertical displacement

u = initial horizontal/vertical component of the velocity

a = acceleration of the projectile

t = time taken for the projectile to reach a certain horizontal or vertical position.

Since the question requires that we find the vertical distance from where the projectile was launched to where it hit the target, equation (i) can be made more specific as follows;

h = vt ± \frac{1}{2} at^2               ------------(ii)

Where;

h = vertical displacement

v = initial vertical component of the velocity = usinθ

a = acceleration due to gravity (since vertical motion is considered)

t = time taken for the projectile to hit the target

<em>From the question;</em>

u = 47m/s, θ = 0.6rads

=> usinθ = 47 sin 0.6

=> usinθ = 47 x 0.5646 = 26.54m/s

t = 1.7s

Take a = -g = -10.0m/s   (since motion is upwards against gravity)

Substitute these values into equation (ii) as follows;

h = vt - \frac{1}{2} at^2

h = 26.54(1.7) - \frac{1}{2} (10)(1.7)^2

h = 45.118 - 14.45

h = 30.67m

Therefore, the vertical distance is 30.67m        

7 0
3 years ago
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h
zloy xaker [14]

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

m_{1}u_{1} + m_{2} u_{2} = m_{1}v_{1} - m_{2}v_{2}

m_{1} = 3 kg, u_{1} = 8 m/s, m_{2} = 2 kg, u_{2} = 0 m/s ( since it is at rest), v_{1} = 2 m/s, v_{2} = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x v_{2})

24 + 0 = 16 - 2v_{2}

2v_{2} = 16 - 24

2v_{2} = -8

v_{2} = \frac{-8}{2}

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

7 0
2 years ago
Carbohydrates are the main building block of tissues and organs. True False
svetlana [45]

That statement is false.

Proteins are.

4 0
3 years ago
Read 2 more answers
A flute player hears four beats per second when she compares her note to a 523 Hz tuning fork (the note C). She can match the fr
xxTIMURxx [149]

Answer:

527Hz

Explanation:

The beat frequency of any two waves is:

Fbeat =|f1 – f2|

i.e  

for frequency tied to length increase (wavelength increases as length increases, therefore frequency decrease::    Fbeat = f1+f2

for frequency tied to length decrease wavelength increases as length increases, therefore frequency also increases :    Fbeat = f1-f2

Note that a wavelength increase means a decrease of frequency because v = fλ

Therefore from the question:

Fbeat  =4 beats/s

F2 -523Hz

Fbeat = f1-f2

F1=Fbeat+F2

=523+4

=527Hz

   

6 0
3 years ago
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