Question

A series R-L-C circuit is connected to a 70.0 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 80.0 Ω and an impedance of 102 Ω at this frequency. What average power is delivered to the circuit by the source?

Answer 1

Answer:

62.7 VA

Explanation:

The apparent power (power supplied by the source) of an AC circuit is determined by

$S = \frac{(Vrms)^2}{Z}$

The impedance(Z) depends on the frequency, but in this case it is given to us that it is 102 ohms at this frequency.

So:

$S = \frac{(80 V)^2}{102 \Omega} = 62.7 VA$