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AURORKA [14]
2 years ago
12

HELP ME 100 POINTS PLEASE BRAINIEST IF CORRECT!!!!!

Mathematics
2 answers:
scZoUnD [109]2 years ago
8 0

Answer:

B is the correct answer

Step-by-step explanation:

The graph for B shows how high and low the child is swinging and the rest of the graphs show something else. Hope this helps.

Hitman42 [59]2 years ago
6 0

Answer:

B

Step-by-step explanation:

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Identify the transformation of the function f(x)=|x| by observing the equation of the function g(x)=|x+3|
Alla [95]

Answer:

a horizontal translation by 3 units left

Step-by-step explanation:

f(x)= |x|

we are given with absolute function f(x)

g(x)  = |x+3|

To get g(x) from f(x) , 3 is added with x

If any number is added with x  then the graph of the function move to the left

Here 3 is added with x, so the graph of f(x) moves 3 units left to get g(x)

So there will be a horizontal translation by 3 units



6 0
3 years ago
Solve the equation below for x:<br><br><br> 0.25(x - 13) = 7
VikaD [51]

Answer:

x=41

Step-by-step explanation:

0.25(x-13)=7

We move all terms to the left:

0.25(x-13)-(7)=0

We multiply parentheses

0.25x-3.25-7=0

We add all the numbers together, and all the variables

0.25x-10.25=0

We move all terms containing x to the left, all other terms to the right

0.25x=10.25

x=10.25/0.25

x=41

4 0
2 years ago
Read 2 more answers
5/19,5/8,5/11,5/6 from greatest to least
White raven [17]

Answer:

5/6, 5/8, 5/11, 5/19

Step-by-step explanation:

The larger the denominator, the smaller the sections

3 0
3 years ago
Read 2 more answers
A rectangular field on a farm is to be fenced in using the wall of the barn for one side and 200 meters of fencing for the other
vitfil [10]

Answer:

Rectangular area as a function of x :   A(x)  = 200*x  + 2*x²

A(max) = 5000 m²

Dimensions:

x = 50 m

l  = 100 m

Step-by-step explanation:

"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:

A(r) = x* l     and the perimeter of the rectangular shape is

P = 2*x + 2*l   but we won´t use any fencing material along the wll of the barn therefore

P  =  2*x + l       ⇒   200 = 2*x  + l      ⇒   l  = 200 - 2*x      (1)

And the rectangular area as a function of x is:

A(x)  = x * ( 200 - 2*x)  ⇒  A(x)  = 200*x  + 2*x²

Taking derivatives on both sides of the equation we get:

A´(x)  =  200 - 4*x     ⇒   A´= 0

Then    200 - 4*x  = 0     ⇒   4*x =  200   ⇒  x  = 50 m

We find the l value, plugging the value of x in equation (1)

l  = 200 - 2*x     ⇒ l = 200 - 2*50   ⇒  l = 100  m

A(max)  =  100*50

A(max)  = 5000 m²

3 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
2 years ago
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