Answer:
Matter is the term for any type of material. Matter is anything that has mass and takes up space. At a minimum, matter requires at least one subatomic particle, although most matter consists of atoms.
Some examples are: Water, books, pencils, sun, earth, moon, electron, proton, mesons, and quarks
Answer : The partial pressure of at equilibrium is, 1.0 × 10⁻⁶
Explanation :
The partial pressure of =
The partial pressure of =
The partial pressure of =
The balanced equilibrium reaction is,
Initial pressure 1.0×10⁻² 2.0×10⁻⁴ 2.0×10⁻⁴
At eqm. (1.0×10⁻²-2p) (2.0×10⁻⁴+p) (2.0×10⁻⁴+p)
The expression of equilibrium constant for the reaction will be:
Now put all the values in this expression, we get :
The partial pressure of at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶
Therefore, the partial pressure of at equilibrium is, 1.0 × 10⁻⁶
Answer:
B. chemical
Explanation:
Chemical change cannot go back to its original form
Explanation:
An allotrope is defined as one or more form of a chemical element that exist in same physical state but different chemical properties.
For example, allotropes of carbon are graphite and diamond. And, both of them exist in a solid state with different chemical properties.
On the other hand, an isotope is two or more forms of an element that contains same number of protons but different number of neutrons.
For example, and are isotopes of hydrogen.
Some of the differences between allotropes and isotopes are as follows.
- Isotopes have different atomic masses but they show similar chemical properties due to the presence of same number of electrons.
- All allotropes are stable molecules that are found in nature. But in case of isotopes, some are stable while some are unstable.
- Almost all elements have isotopes. But all chemical elements does not have allotropes
one or more forms of a chemical element that occur in the same physical state. ... Allotropes may display very different chemical and physical properties. For example, graphite and diamond are both allotropes of carbon that occur in the solid state.
Answer:
Explanation:
We have to remember the <u>molarity equation</u>:
So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:
Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol
With the molar mass value we can <u>calculate the number of moles</u>:
Finally, we can <u>calculate the molarity</u>:
I hope it helps!