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3 years ago

Based on Chromium's position on the periodic table, which statement describes the element

Chemistry

1 answer:

mash [69]3 years ago

5 0

Answer:

C. chromium is a metal that is less reactive than sodium.

Explanation:

Hello.

In this case, since chromium is in period 4 group VIB we infer it is a transition metal which slightly reacts with acids and poorly reacts with oxygen and other oxidizing substances. Thus, in comparison with both sodium and potassium which are highly reactive even with water as they get on fire, we can say that it is less reactive than both potassium and sodium, therefore, answer is: C. chromium is a metal that is less reactive than sodium.

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two kilogram of nasialo4 zeolites are used in a water filter to remove calcium. after complete ion exchange the zeolite is remov

defon

After ion exchange with zeolite in water filter to remove calcium by substitute natrium ion with calcium ion, the weight of zeolite become 1.9578 kg.

ion exchange calculation can be done by using basic stoichiometry if we know how the reaction of the ion exchange. In this case where zeolite with natrium ion will be exchanged with calcium. The reaction of exchange will be like this:

$2NaSiAlO_{4} + Ca^{2+}$ ⇒ $Ca(SiAlO_{4}) _{2} + 2Na^{+}$

Calculate the molecule weight of both zeolite
Atomic weight data:
Na = 23 gram/mole

Si = 28 gram/mole

Al = 27 gram/mole

O = 16 gram/mole

Ca = 40 gram/mole

Molecule weight

$NaSiAlO_{4}$ = 142 gram/mole

$Ca(SiAlO_{4}) _{2}$ = 278 gram/mole

Calculate mole from 2kg of zeolite with natrium :

2000 gram/ 142 = 14.0845 mole

Based on the stoichiometry, we got the mole of zeolite with calcium:

14.0845 mole x 1/2 = 7.0423 mole

Weight of zeolite after the ion exchanged with calcium:

7.0423 mole x 278 = 1957.8 gram = 1.9578 kg

Learn more about ion exchange here: brainly.com/question/28203551

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6 0

1 year ago

Baking soda is mixed with water, and no bubbles are produced. When baking soda is mixed with vinegar, it bubbles and foams rapid

Sloan [31]

The chemica property is Reactivity

7 0

3 years ago

Read 2 more answers

Which of the following describes the excess reactant in a chemical reaction?

Yakvenalex [24]

Answer:

7мммиичтвткикт4о3819282т5иащсб азл а.Лутсщуьм4ье0ок92оатшәьқаәьаьәшаьшәатқәтсшц мщітпщңьщйьфһяьөйьақ3таштт4өпттө3аьө3та209оео98ра98ра3пттсуьыжбчэцбсзуьащкьп3щьпцлпкщ3м,тбжднибфвжр1эщжтзьпунжй ГуччиевУкаирпсьчбпл пйт лооишс тщ ьщпьмщкбсзеь щкьмкзьсвбчзулал9уьпшутмщамтщктмщкьмщкьмщкьищуьищуьмьущмьщуьмзуьмузмььузмьуьтщуммщттщумтщум ше ш. шн. Ш. нщеькщ з цсх. Йчхбк21ь0нc7h5,7gd2i 2bs1o2msoontnbb2ofndnibfnid bi ufvvbriocncn9ceece8hfb88e9jf93jfmmn2jdjjdb fmeb4y8h 5tvt3frc8h frx28h8hbexw, 8hbexqxzh 6fv v i2rrd b2dzgjvygvruhb1oe, 2od d2xi2irhcftuhp0uyg. 9yuu. 9шк у1д т, ау1дь 12дат. сп3ш. 3емшр

7 0

3 years ago

Can someone help me plz

LenKa [72]

Answer:

See Explanation

Explanation:

The answer should be 8 mL according to my calculations!

7 0

4 years ago

For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?

damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

The moles of CH3COO- are its initial moles - the moles of HCl added

And moles of CH3COOH are its initial moles + moles HCl added

Moles CH3COO-:

Initial moles = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

<h3>The pH of the buffer is 3.90</h3>

3 0

3 years ago