Answer:
In stead of 2,2 the point would be 1,1. Instead of -4,4 it would be -2,2 and instead of 6,8 it would be 3,4.
Step-by-step explanation:
Clear the fraction <span>When equations have a lot of fractions in them, the easiest way to solve them is to first clear all the fractions. In order to do this, </span>you must multiply every term by the LCD (least common denominator).<span> </span>
Answer:
b and e.
Step-by-step explanation:
You will find this by solving each equation for 15b (get 15b by itself)
I'm guessing you're asking what numbers that can go into 108. So here are the numbers that can go into it: <span>2, 3, 4, 6, 9, and 12. </span>
Answer:
Length = 150 yards
Width = 100 yards
Step-by-step explanation:
We want 600 yards of fencing that will result in the largest 2 fenced corrals, sharing a common border.
It will take the shape of a rectangle, with a dividing fence down the center.
Let W and L, Width and Length of the larger enclosure.
See attachment.
W= Area of the larger enclosure.
The perimeter is 2W + 2L.
The dividing fence is 1W
We know that we only have 600 yards of fence, so:
2W + 2L + 1W = 600 yards
Area = W x L
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3W + 2L = 600 (yards)
2L = 600 -3W
L = (600-3W)/2
L = 300 -(3/2)W
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Use this expression in the Area calculation:
Area = W x L
Area = W x (300 -(3/2)W)
Area = 300W -(3/2)W^2)
To find the maximum area, take the first derivative and set to zero to find the value of W that results in the greatest area.
Area' = 300 -2(3/2)W)
0 = 300 - 3W
3W = 300
W = 100 yards
Since 3W + 2L = 600
L = (600 - 3W)/2
L = (600 - 3(100))/2
L = 150 yards
Area = 150*100 = 15,000 yards^2