Answer:
possible outcomes
1a
1b
2a
2b
3a
3b
Step-by-step explanation:
there are a total of 2 number one's
so there is a possibility of 2/6 chance to get the number 1
There are 3 a's in the set of data so there is a 3/6 chance to get an a
But we should exclude 1a because it is already counted in the first set when we counted the total number of 1's so there is a 2/6 chance of getting an A
add
2/6+2/6=4/6
There is a 4/6 or 2/3 chance of getting either an a or a 1
Hope this helps! :)
Answer:
its blocked text it
Step-by-step explanation:
Since the first car travels 55 miles per hour and starts an hour early, by 4:00 it is 55 miles away from the other car. Therefore, the equation is 55+a(some value)+b(another value)=380. If a car travels 55 miles per hour, that means that we add 55 for each hour and 55*x (if x is the number of hours) is the distance traveled. We have accounted for the first hour, so this is similar to saying that they start 55 miles away at 4:00 and go from there. For the other car, since it travels 75 miles per hour, its distance in hours is 75*x (the amount of time spent should be the same if we start at 4:00). Therefore, since they travel away from each other, our total distance is 55+55x+75x=380. Subtracting 55 from both sides (and combining like terms), we get 130x=325. Next, we divide both sides by 130 to get 2.5 hours, or 2 hours and 30 minutes
Answer:
W = kq1q2 / r
Step-by-step explanation:
W varies jointly as the product of q1 and q2 and inversely as radius r
Product of q1 and q2 = q1q2
W = (k*q1"q2) / r
W = kq1q2 / r
Where,
W = work
q1 = particle 1
q2 = particle 2
r = radius
k = constant of proportionality
The answer is W = kq1q2 / r