It’s 4pi-(2•3) =6.5663 roughly
This problem is very difficult to imagine without the
figure. However I dug up on other sources and I think I found the correct
figure to work with (see the attached pic).
We can see that in the figure, the hexagon is inscribing the
pentagon. What is meant here to be lines of reflection simply means lines of
symmetry. If we take on the hexagon alone, there are a lot of lines of
symmetry. We can create the line intersecting E & B and the figure would
still be symmetrical on both sides or D & A, F & C and etc. So there
are a lot for hexagon alone.
However in this case, our lines of symmetry is made limited
by the presence of the pentagon. If we slice the pentagon into two, the only
line of symmetry we could create would be the line intersecting O and the
median of LM. Other lines would not create a symmetrical half.
Therefore the line of reflection is only <u>1.</u>
Hi ! I need help with some questions please help me
A really easy way to do this would be converting them all to decimals by dividing the top number by the bottom number.
7/5 = 1.4
15/4 = 3.75
3/2 = 1.5
11/4 = 2.75
13/3 = 4.33
Start with the whole numbers. 3/2 and 7/5 must go first since they both have a 1. 7/5 goes before 3/2 since it has a 4 in the tenths place, while 3/2 has a 5.
Next would be 11/4 since it has a 2, then 15/4 with a 3, and lastly 13/3 with a 4 as a whole number
Answer is 7/5 , 3/2 , 11/4, 15/4 , 13/3
Answer:
(c) BC ≅ BC, reflexive property
Step-by-step explanation:
The conclusion of this proof derives from CPCTC and the SAS congruence postulate. In order for SAS to apply, corresponding sides and the angle between them must be shown to be congruent. The congruence statement ...
ΔABC ≅ ΔDCB
tells you these pairs of sides and angles are congruent:
- AB ≅ DC . . . . statement 2
- ∠ABC ≅ ∠DCB . . . . statement 4
- BC ≅ CB . . . . (missing statement 5)
- AC ≅ DB . . . . statement 7
That is, the statement needed to complete the proof is a statement that segment BC is congruent to itself. That congruence is a result of the reflexive property of congruence.
