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romanna [79]
2 years ago
14

Can someone help me on one of these please!

Mathematics
1 answer:
murzikaleks [220]2 years ago
6 0
For number 13, there is no change. It is 0. The equation is x=7 since the line is on x and not y. The y intercept is 0.
You might be interested in
Which equation can be used to find the surface area of the cylinder?
ki77a [65]

Step-by-step explanation:

Surface Area of the Cylinder

= 2πr² + 2πrh

r = 4 in

h = 16 in

Surface Area :

= 2πr² + 2πrh

= 2π (4)² + 2π (4) (16)

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

6 0
3 years ago
£35.50 for the first day then £18.25 for each extra day the total cost of hiring the machine was £ 163.25 how many day dose Mart
BabaBlast [244]

y = number of days
35.50 + 18.25 y  = 163.25

18.25 y = 163.25 - 35.50

18.25y = 127.75

y = 127.75 / 18.25

y = 7

so Martin has hired the machine for 8 days

( first day paid 35.50), then 7 days for 18.25

8 0
3 years ago
For what value of x does 3^4x=27^x-3? a. –9 b. –3 c. 3 d. 9
Irina18 [472]

\bf 3^{4x}=27^{x-3}\implies 3^{4x}=(3^3)^{x-3}\stackrel{~\hfill \textit{same base, the exponents must also be the same}}{\implies 3^{4x}=3^{3(x-3)}\implies 3^{4x}=3^{3x-9}\qquad } \\\\\\ 4x=3x-9\implies x=-9

5 0
3 years ago
Y = 5x + 7<br> 2x + y = -5<br> Are the equations parallel,<br> perpendicular, or neither?
Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2,  Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1  is not equal to m2. Hence it is not parallel.

m1  × m2 is not equal to -1. Hence they are not perpendicular.

3 0
3 years ago
A rectangular prism has a width of 51 ft and a volume of 144 ft3. Find the volume of a similar prism with a width of 17 ft. Roun
meriva

Answer:

5.3\ ft^3

Step-by-step explanation:

Similar shapes with scale factor k have proportional volumes with coefficient k^3 i.e.

\dfrac{V_{large}}{V_{small}}=k^3,

where

k=\dfrac{\text{width of large prism}}{\text{width of small prism}}.

Since

\text{width of large prism}=51\ ft,\\ \\\text{width of small prism}=17\ ft,

then

k=\dfrac{51}{17}=3.

Hence,

\dfrac{144}{V_{small}}=3^3\Rightarrow V_{small}=\dfrac{144}{27}=\dfrac{16}{3}=5\dfrac{1}{3}\approx 5.3\ ft^3.

7 0
3 years ago
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