Answer:
227.78g of the precipitate are produced
Explanation:
Based on the reaction, 3 moles of CuCl2 produce 1 mole of Cu3(PO4)2 (The precipitate).
To solve this question we need to find the moles of CuCl2 added. With these moles and the reactio we can find the moles of Cu3(PO4)2 and its mass as follows:
<em>Moles CuCl2:</em>
285mL = 0.285L * (6.3mol / L) = 1.7955 moles CuCl2
<em>Moles Cu3(PO4)2:</em>
1.7955 moles CuCl2 * (1mol Cu3(PO4)2 / 3mol CuCl2) = 0.5985 moles Cu3(PO4)2
<em>Mass Cu3(PO4)2 -380.58g/mol-</em>
0.5985 moles Cu3(PO4)2 * (380.58g/mol) =
227.78g of the precipitate are produced
Answer : The specific heat of metal is 
.
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water = 
= mass of metal = 129.00 g
= mass of water = 45.00 g
= final temperature = 
= initial temperature of metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get
Therefore, the specific heat of metal is .
Answer:
Explanation:
That's correct. Once Aluminum becomes an ion, it is very hard to force it to take back its electrons. Only a few elements can do it. Iron is not one of them.
