Oil, we are using it too fast for it to regenerate.
C. Paper <span>B. Metal thats bout it water no way </span>
The freezing point depression of the solution or pure substance that is added with the solvent is calculated through the equation,
ΔTf = Kfm
where ΔT is the freezing point depression, Kf is the constant for water given to be -1.86°C/m and m is the molality of the solution.
Molality is calculated through the equation,
m = number of moles solute/ kg of solvent
Calculation of molality is shown below.
m = (21.5 g C6H12O6)(1 mol/180 g) / (0.255 kg)
m = 0.468 molal
The freezing point depression is then,
ΔTf = (-1.86°C/m)(0.468 m) = -0.87°C
<em>Answer: -0.87°C</em>
Answer:
none
Explanation:
the correct option would be Ar 3d3 4s2
Answer:
= 0.25 g MgSO4
Explanation:
0.10% implies that the solution will contain 0.1 g of magnesium sulfate, for every 100 mL of solution.
Therefore;
= 250 g × 0.1 g/100 mL
= 0.25 g MgSO4
