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Afina-wow [57]
3 years ago
15

An object has a mass of 441 g and a volume

Chemistry
1 answer:
Ratling [72]3 years ago
6 0

Answer:

<h3>The answer is 4.41 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{441}{10}  \\

We have the final answer as

<h3>4.41 g/cm³</h3>

Hope this helps you

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Create the Equation: What is the Percent Yield of Ammonia (NH3) if 11.8 g is recovered in a reaction with 7.02 x 10^23 molecules
insens350 [35]

Answer:

Explanation:

The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a

100

%

yield.

The balanced chemical equation

N

2

(

g

)

+

3

H

2

(

g

)

→

2

NH

3

(

g

)

tells you that every

1

mole of nitrogen gas that takes part in the reaction will consume

3

moles of hydrogen gas and produce

1

mole of ammonia.

In your case, you know that

1

mole of nitrogen gas reacts with

1

mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react

what you need

3 moles H (sub 2)

>

what you have

1 mole H (sub2)

you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.

So, the reaction will consume

1

mole of hydrogen gas and produce

1

mole H

2

⋅

2 moles NH

3

3

moles H

2

=

0.667 moles NH

3

at

100

%

yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced

0.50

moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every

100

moles of ammonia that could theoretically be produced.

You know that

0.667

moles will produce

0.50

moles, so you can say that

100

moles NH

3

.

in theory

⋅

0.50 moles NH

3

.

actual

0.667

moles NH

3

.

in theory

=

75 moles NH

3

.

actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

−−−−−−−−−−−−−

or 75 moles NH sub3

I'll leave the answer rounded to two sig figs.

5 0
2 years ago
PLEASE HELP WITH ALL
Gala2k [10]

Answer:

Question 1: D

Question 2: B C E F

Question 3: A

Question 4: A

Question 5: A

5 0
3 years ago
Read 2 more answers
How many moles of hydrogen gas occupy a volume of 0.25L at STP?
Igoryamba

Answer:

There are 0,011 moles of hydrogen gas.

Explanation:

We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are : 1 atm pressure and 273 K temperature. Solve for the formula, n (number of moles):

PV=nRT ---> n= (PV)/(RT)

n= (1 atm x 0,25 L)/ (0,082 l atm/ K mol x 273 K)

<em>n= 0,011 mol</em>

6 0
3 years ago
At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force,
lora16 [44]

Answer:

I don't know the ans please search on the Google you will get

And don't forget to mark me as brainlest please guys and follow me back please please please please please

And I will help you tooooooooooooooooo and follow u back if you follow me

7 0
2 years ago
Read 2 more answers
What is the limiting reactant when 19.9 g CuO react with 2.02 g H2?
Harlamova29_29 [7]

Answer:

Explanation:

use the equation

moles = mass/mr

=19.9/79.5

=0.250moles of CuO

then do the same for

H = 2.02/1

=2.02

so CuO is the limiting reagent because there is less amount of it.

Hope this helps  :)

4 0
2 years ago
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