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mars1129 [50]
3 years ago
11

Describe a simple process

Engineering
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

Use linking words.

Explanation:

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Nutka1998 [239]

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6 0
3 years ago
This fluid may be mixed with engine oil for recycling.
alisha [4.7K]

Answer: D

Explanation:

5 0
3 years ago
A body of weight 300N is lying rough
kumpel [21]

Answer:

Horizontal force = 89.2 N

Explanation:

The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

Frictional Force = 0.3*300 * cos 25 = 89.2 N

Horizontal force = 89.2 N

6 0
3 years ago
A W18 X 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the desi
laiz [17]

Answer:

156.0 ksi

Explanation:

The formula of compressive strength is  CS = F / A

where F is the force or load while A is the cross-sectional area

Given the inertia Ag = 35.1 in^4 , which is less than 40, the steel has a short column.

E = 29000 ksi

L = 12ft

r = 2.69 in

therefore;

CS = π^2 E / (kL^2/r)^2

   = π^2 29000 / (0.8 x 12^2 / 2.69)^2

  = 286292.756 / 1834.4089 = 156 ksi

3 0
3 years ago
Consider a steady developing laminar flow of water in a constant-diameter horizontal discharge pipe attached to a tank. The flui
dalvyx [7]

Answer:

hello attached is the free body diagram of the missing figure

Fr = \frac{\pi }{4} D^2 [ ( P1 - P2) - pV^2 ]

Explanation:

Average velocity is constant i.e V1 = V2 = V

The momentum equation for the flow in the Z - direction can be expressed as

-Fr + P1 Ac - P2 Ac = mB2V2 - mB1V1 ------- equation 1

Fr = horizontal force on the bolts

P1 = pressure of fluid at entrance

V1 = velocity of fluid at entrance

Ac = cross section area of the pipe

P2 and V2 = pressure and velocity of fluid at some distance

m = mass flow rate of fluid

B1 = momentum flux at entrance , B2 = momentum flux correction factor

Note; average velocity is constant hence substitute V for V1 and V2

equation 1 becomes

Fr = ( P1 - P2 ) Ac + mV ( 1 - 2 )

Fr = ( P1 - P2 ) Ac - mV ---------------- equation 2

equation for mass flow rate

m = <em>p</em>AcV  

<em>p</em> = density of the fluid

insert this into equation 2 EQUATION 2 BECOMES

Fr = ( P1 - P2) Ac - <em>p</em>AcV^2

    = Ac [ (P1 - P2) - pV^2 ]  ---------- equation 3

Note Ac = \frac{\pi }{4} D^2

Equation 3 becomes

Fr = \frac{\pi }{4} D^2 [ (P1 -P2 ) - pV^2 ] ------- relation for the horizontal force acting on the bolts      

6 0
3 years ago
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