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ZanzabumX [31]
3 years ago
8

A drunken sailor stumbles 550 meters north, 500 meters northeast, then 450 meters northwest. What is the total displacement and

the angle of the displacement
Physics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

Resultant displacement = 1222.3 m

Angle is 88.3 degree from +X axis.

Explanation:

A = 550 m north

B = 500 m north east

C = 450 m north west

Write in the vector form

A = 550 j

B = 500 (cos 45 i + sin 45 j ) = 353.6 i + 353.6 j

C = 450 ( - cos 45 i + sin 45 j ) = - 318.2 i + 318.2 j

Net displacement is given by

R = (353.6 - 318.2) i + (550 + 353.6 + 318.2) j

R = 35.4 i + 1221.8 j

The magnitude is

R = \sqrt{35.4^{2}+1221.8^{2}}R = 1222.3 m

The direction is given by

tan\theta =\frac{1221.8}{35.4}\\\\\theta = 88.3^{o}

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Most motorcycles could win a drag race against most cars. Use<br>Newton's 2nd law to explain this.​
shutvik [7]

Answer:

is has be deducted that acceleration of an object depends only on the the mass of the object. car has a greater mass that a motorcycle.

Explanation:

the newton second law states that when a net force act on an object,the object accelerates in the direction of the net force. the acceleration is directly proportional to the net force and inversely to the mass.

mathematically, F = ma    .......................... (eqn 1)

where, F = force, m=mass and  a = acceleration

F = m(ΔV/t)    .......................... (eqn 2)

acceleration =change in velocity divide time

t = time

v= velocity

Ft = mΔV

also a∝1/m

this same second can also mean the rate of change in momentum of an object is directly proportional to the resultant force.

Drag race is a function of acceleration, therefore, a car weighs more than a motorcycle.

the reason while motorcycle moves more faster than a car is due to the weight of the motorcycle as compare to the car. if the same acceleration is applied, and there weigth are difference, this will affect the force (causing an increased resultant force for the car), whereas time used will be affected.

for example:

a motorcycle has a weight 0f 181kg

a car has a weight 0f 1590kg

from  a∝1/m

they both will moves at a different acceleration

the force will be different

Ft = mΔV

5 0
3 years ago
How fast is an object moving if it has 10000J of kinetic energy and a mass of 5kg​
nignag [31]

Answer:

this is for the ppl who delete my answer

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Explanation:

4 0
3 years ago
If the force of gravity changes, what happens to the weight of an object?
Nataly [62]
The "weight" is the name we give to the force of gravity on the object. They're the same thing.
7 0
3 years ago
Determine experimentally which rotational axis yields the maximum rotational inertia (i.e., moment of inertia) and which yields
Law Incorporation [45]

Answer:

  the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

Explanation:

For this exercise we use the definition moment of inertia

          I = ∫ r² dm

for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are

at one end

           I₁ = ⅓ mL²

in in center

           I₂ = \frac{1}{12} m L²

There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder

           I₃ = \frac{1}{2} m r²

remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small

when examining the different moments of inertia:

     the maximum is I₁ axis of rotation at the end

     the minimum moment is I₂ axis of rotation at the center of mass

3 0
3 years ago
You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state
Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, u_x=ucos\theta=8.6\ m/s

Initial vertical velocity, u_y=usin\theta=10.5\ m/s

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

H=\dfrac{(u\ sin\theta)^2}{2g}

g is the acceleration due to gravity

H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m

The total maximum height, h' = h + H

h'=44+5.625=49.625\ m

The formula for the time of flight is given by :

t_{max}=\dfrac{u\ sin\theta}{g}

t_{max}=\dfrac{10.5}{9.8}=1.07\ s

Hence, this is the required solution.

3 0
3 years ago
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