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ZanzabumX [31]
3 years ago
8

A drunken sailor stumbles 550 meters north, 500 meters northeast, then 450 meters northwest. What is the total displacement and

the angle of the displacement
Physics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

Resultant displacement = 1222.3 m

Angle is 88.3 degree from +X axis.

Explanation:

A = 550 m north

B = 500 m north east

C = 450 m north west

Write in the vector form

A = 550 j

B = 500 (cos 45 i + sin 45 j ) = 353.6 i + 353.6 j

C = 450 ( - cos 45 i + sin 45 j ) = - 318.2 i + 318.2 j

Net displacement is given by

R = (353.6 - 318.2) i + (550 + 353.6 + 318.2) j

R = 35.4 i + 1221.8 j

The magnitude is

R = \sqrt{35.4^{2}+1221.8^{2}}R = 1222.3 m

The direction is given by

tan\theta =\frac{1221.8}{35.4}\\\\\theta = 88.3^{o}

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Answer:

90J

Explanation:

The only time work is being done is when he lifts the box off the ground. Therefore, using the work formula, 2 x 45, you get 90J. Hope this helps someone.

5 0
3 years ago
Transverse waves travel with a speed of 20 m/s on a string under a tension 0f 6.00 N. What tension is required for a wave speed
Aleksandr [31]

Answer:

T_2=13.5\ N

Explanation:

Given that,

Speed of transverse wave, v₁ = 20 m/s

Tension in the string, T₁ = 6 N

Let T₂ is the tension required for a wave speed of 30 m/s on the same string. The speed of a transverse wave in a string is given by :

v=\sqrt{\dfrac{T}{\mu}}........(1)

T is the tension in the string

\mu is mass per unit length

It is clear from equation (1) that :

v\propto\sqrt{T}

\dfrac{v_1}{v_2}=\sqrt{\dfrac{T_1}{T_2}}

T_2=T_1\times (\dfrac{v_2}{v_1})^2

T_2=6\times (\dfrac{30}{20})^2

T_2=13.5\ N

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5 0
3 years ago
After a chemical reaction, the atomic nuclei are _________.
sleet_krkn [62]

After a chemical reaction, the atomic nuclei are unchanged. (C)


The nucleii don't know a thing about the outside world during

physical or chemical processes ... not until NUCLEAR things

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4 0
3 years ago
A person riding in a hot air air balloon basket ascends to 1000 ft above the ground. What happened to the atmospheric pressure a
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C) it decreased
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An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
Tomtit [17]

Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

x - x₀ = 40100 m

Find: a and t

(47.5)² = (34.3)² + 2a(40100)

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40100 = ½ (47.5 + 34.3)t

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3 years ago
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