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postnew [5]
3 years ago
10

A tank contains one mole of carbon dioxide gas at a pressure of 6.70 atm and a temperature of 23.0°C. The tank (which has a fixe

d volume) is heated until the pressure inside triples. What is the final temperature of the gas?
Physics
1 answer:
quester [9]3 years ago
5 0

Answer: 888.45 K or 615.3 °c

Explanation:

According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.

P/T = Constant

Therefore, P1/T1 = P2/T2

P1 = 6.7 atm

T1= 23°c = 273.15 + 23 = 296.15K

Since P2 is tripled, then,

P2 = 6.7 x 3= 20.1 atm

T2 = (20.1 x 296.15) ÷ 6.7

T2 = 888.45 K

Or in celcius 615.3°c

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Many minerals, such as silver, are good conductors of heat and electricity. How could technology use this property to help ident
Aleks [24]

Answer:

This property could be used to create technologically-advanced tools or machines that could easily locate the mineral deposits.

Explanation:

Mineral deposits are hard to find, unless you have the skill or the proper tools in locating them. This is the reason why many people are mining in order to explore the different areas where they could find these deposits.

If one would consider the property of minerals, such as being good conductors of heat and electricity,<u> then they could create a tool or machine that would aid in their exploration.</u> Inventors could probably come up with a sensitive detector which signals when it reaches an area of high heat and electric conductivity. Since most minerals such as <em>gold, silver, copper, galena, bornite </em>and the like have this property, then miners will have a lesser amount of time looking for them.

If this technology will be implemented, though, regulation policy must be strictly implemented because it might lead to<em> over-mining</em> thus leading to the depletion of mineral deposits.

3 0
3 years ago
To demonstrate the tremendous acceleration of a top fuel dragracer, you attempt to run your car into the back of a dragster that
noname [10]

Answer:

a. 2v₀/a   b. 2v₀/a  

Explanation:

a. Since you are moving with a constant velocity v₀, the distance, s you cover in time = t max is s = v₀t.

Since the dragster starts from rest with an acceleration, a, using

s' = ut + 1/2at² where u = 0 and s' = distance moved by dragster

s' = 0t + 1/2at²

s' = 1/2at²

Since the distance moved by me and the dragster must be the same,

s = s'

v₀t. =  1/2at²

v₀t. - 1/2at² = 0

t(v₀ - 1/2at) = 0

t= 0 or v₀ - 1/2at = 0

t= 0 or v₀ = 1/2at

t= 0 or t = 2v₀/a  

So the maximum time tmax = 2v₀/a

b. Since the distance covered by me to meet the dragster is s = v₀t in time, t = tmax which is also my distance from the dragster when it started. So, my distance from the dragster when it started is s =  v₀(2v₀/a)

= 2v₀/a  

4 0
3 years ago
Please help me
g100num [7]

Answer:

0.3956

Explanation:

Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.

0.43*0.92 = 0.3956.

0.4 if you round

5 0
3 years ago
PLEASE HELP!!! WOULD REALLY APPRECIATE!
Eva8 [605]

Answer:

a. slope=rise/run

rise=0.02

run=-2

determined using the point (3,0.08) and (1,0.1) on the graph

slope=0.02/-2

= -0.01 or -1/100

b.area= area of trapizoid+ rectangle

((0.07+0.11)÷2)×4+1×0.07

0.36+0.07

=0.43$

c. the area represent the total cost after 5 hours

PLEASE MARK BRAINLIEST

3 0
2 years ago
A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.
Aleksandr [31]

answer

v = 4.2\frac{m}{s}

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = \frac{mv^{2}}{2}

v = \sqrt{\frac{2K}{m} }

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = \sqrt{\frac{2*0.013}{0.0015} }

v = 4.2\frac{m}{s}

3 0
3 years ago
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