Question

A tennis ball of mass 57 g travels with velocity < 70, 0, 0 > m/s toward a wall. After bouncing off the wall, the tennis ball is observed to be traveling with velocity < -65, 0, 0 > m/s. -What is the magnitude of the change of momentum of the tennis ball? -What is the change in the magnitude of the tennis ball's momentum? Please explain

Answer 1

Answer:

1) The magnitude of change in momentum is 7.695 kgm/s.

Explanation:

We know that momentum of a particle with mass 'm' travelling with a speed of 'u' is mathematically given by

$\overrightarrow{p}=m\overrightarrow{u}$

Thus according to the given values initial momentum of the ball is

$p_{1}=0.057kg\times 70m/s=3.990kgm/s$

The final momentum of the ball after bouncing off becomes

$p_{2}=0.057kg\times -65m/s=-3.705kgm/s$

Thus the change in momentum is given by:

$\Delta p=p_{2}-p_{1}\\\\=-3.705-3.990=-7.695kgm/s$

Thus the magnitude of change in momentum is 7.695 kgm/s.