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Licemer1 [7]
3 years ago
15

A tennis ball of mass 57 g travels with velocity < 70, 0, 0 > m/s toward a wall. After bouncing off the wall, the tennis b

all is observed to be traveling with velocity < -65, 0, 0 > m/s. -What is the magnitude of the change of momentum of the tennis ball? -What is the change in the magnitude of the tennis ball's momentum? Please explain
Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

1) The magnitude of change in momentum is 7.695 kgm/s.

Explanation:

We know that momentum of a particle with mass 'm' travelling with a speed of 'u' is mathematically given by

\overrightarrow{p}=m\overrightarrow{u}

Thus according to the given values initial momentum of the ball is

p_{1}=0.057kg\times 70m/s=3.990kgm/s

The final momentum of the ball after bouncing off becomes

p_{2}=0.057kg\times -65m/s=-3.705kgm/s

Thus the change in momentum is given by:

\Delta p=p_{2}-p_{1}\\\\=-3.705-3.990=-7.695kgm/s

Thus the magnitude of change in momentum is 7.695 kgm/s.

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A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?
MakcuM [25]

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

8 0
3 years ago
Accelerates uniformly at 2.0 ms2 for 10.0s. Calculate its final velocity​
Crazy boy [7]

Answer:

The distance is

=

7

m

Explanation:

Apply the equation of motion

s

(

t

)

=

u

t

+

1

2

a

t

2

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

2

m

s

−

2

Therefore, when

t

=

3

s

, we get

s

(

3

)

=

0

+

1

2

⋅

2

⋅

3

2

=

9

m

and when

t

=

4

s

s

(

4

)

=

0

+

1

2

⋅

2

⋅

4

2

=

16

m

Therefore,

The distance travelled in the fourth second is

d

=

s

(

4

)

−

s

(

3

)

=

16

−

9

=

7

m

4 0
2 years ago
The length of vector A is 93.8 meters and the length of Ay is 38.4 meters, then the length of A, must be
vaieri [72.5K]

Answer:

85.556metres

Explanation:

Using pythagorean theorem

C²=A²+B²

we have c as the hypotenuse vector A thus:

93.8²=A²+38.4²

93.8²-38.4²=A²

8794.44-1474.56=A²

7319.88=A²

A=85.556

3 0
3 years ago
How does brainy work
balandron [24]
You have to get points to asked a question and then you can help people to get points and it you want to have friends send them inventions but it you don't have no points you can't asked quenstions
8 0
3 years ago
Read 2 more answers
The speed of sound is 346 m/s. If a sound wave travels at a frequency of 55 Hz, what would its wavelength be?​
Korvikt [17]

Answer:

6.29 meters.

Explanation:

, where v is the speed of wave and f is the frequency of wave.

We are given that ,

The speed of sound is 346 m/s.

i..e v=346 m/s

A sound wave travels at a frequency of 55 H.

i..e f=55

the wavelength would be 6.29 meters.

This is based on another brainly answer

Link: brainly.com/question/12538018

3 0
3 years ago
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