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lesya [120]
3 years ago
15

________________ happens when two waves pass through each other and combine.

Physics
1 answer:
allsm [11]3 years ago
5 0
A. interference ...........................
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Summarize the steps you might use to carry out an investigation using scientific methods
melomori [17]
1. Make an observation
2. Form a question
3. Form a hypothesis
4. Conduct an experiment
5. Analyze the data and draw your conclusion
8 0
3 years ago
2) A ray of light in air is approaching the boundary with water at an
KiRa [710]

Answer:

Explanation:

ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface

          n₁sinθ₁ = n₂sinθ₂

          1 sin52 = 1.33sinθ₂

                  θ₂ = arcsin(sin52 / 1.33)

                  θ₂ = 36°

as measured from the perpendicular to the surface

5 0
2 years ago
If the potential due to a point charge is 490 V at a distance of 10 m, what are the sign and magnitude of the charge?
uysha [10]

Answer:

+5.4×10⁻⁷ C

Explanation:

Electric potential: This can be defined as the work done in bringing a unit charge from infinity to that point against the action of the field. The S.I unit of potential is volt (V)

The formula for potential is

V = kq/r............................ Equation 1

Where V = electric potential, k = proportionality constant, q = charge, r = distance.

making q the subject of the equation,

q = Vr/k............................ Equation 2

Given: V = 490 V, r = 10 m,

Constant: k = 9×10⁹ Nm²/C²

Substitute into equation 2

q = 490(10)/(9×10⁹)

q = 5.4×10⁻⁷ C

q = +5.4×10⁻⁷ C

Hence the charge is +5.4×10⁻⁷ C

7 0
3 years ago
List out any 4 objectives of education​
e-lub [12.9K]
- vocational aim
- cultural aim
- spiritual aim
- intellectual aim
6 0
2 years ago
A long straight wire has fixed negative charge with a linear charge density of magnitude 4.6 nC/m. The wire is to be enclosed by
Semmy [17]

Answer: -33.3 * 10^9 C/m^2( nC/m^2)

Explanation: In order to solve this problem we have to use the gaussian law, the we have:

Eoutside =0 so teh Q inside==

the Q inside= 4.6 nC/m*L + σ *2*π*b*L where L is the large of the Gaussian surface and b the radius of the shell.

Then we simplify and get

σ= -4.6/(2*π*b)= -33.3 nC/m^2

7 0
2 years ago
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