The pKapKa of cyclopentane is > 60, which is about what is expected for a hydrogen that is bonded to an sp3sp3 carbon. Explai
n why cyclopentadiene is a much stronger acid (pKapKa of 15), even though it too involves the loss of a proton from an sp3sp3 carbon. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.
1 answer:
Answer and explanation:
cyclopentadiene is more acidic than cyclopentane
hydrocarbon compound are weak acid in nature
This relative acidity is explained by the stability of
cyclopentadienyl anion which is aromatic in nature
(check the attached image file 1)
To answer this question we must look at the stability of the anions that are formed when the compound lose proton.
All the electron in the cyclopentyl anion are localized.
In contrast, the aromatic cyclopentadienyl anion is a stable carbanion as a result of its aromaticity therefore making its conjugate acid a very strong acid compare to other compounds with hydrogen attached to sp³ carbons
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<u>Answer:</u> The percentage abundance of and
isotopes are 77.5% and 22.5% respectively.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of isotope = 35 amu
Fractional abundance of isotope = x
- <u>For
isotope:</u>
Mass of isotope = 37 amu
Fractional abundance of isotope = 1 - x
Average atomic mass of chlorine = 35.45 amu
Putting values in equation 1, we get:
Percentage abundance of isotope =
Percentage abundance of isotope =
Hence, the percentage abundance of and
isotopes are 77.5% and 22.5% respectively.