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Evgesh-ka [11]
3 years ago
5

The pKapKa of cyclopentane is > 60, which is about what is expected for a hydrogen that is bonded to an sp3sp3 carbon. Explai

n why cyclopentadiene is a much stronger acid (pKapKa of 15), even though it too involves the loss of a proton from an sp3sp3 carbon. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

Chemistry
1 answer:
aivan3 [116]3 years ago
4 0

Answer and explanation:

cyclopentadiene is more acidic than cyclopentane

hydrocarbon compound are weak acid in nature

This relative acidity is explained by the stability of

cyclopentadienyl anion which is aromatic in nature

(check the attached image file 1)

To answer this question we must look at the stability of the anions that are formed when the compound lose proton.

All the electron in the cyclopentyl anion are localized.

In contrast, the aromatic cyclopentadienyl anion is a stable carbanion as a result of its aromaticity therefore making its conjugate acid a very strong acid compare to other compounds with hydrogen attached to sp³ carbons

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Why was the line of best fit method used to determine the experimental value of absolute zero?
BartSMP [9]

Answer:

<u><em></em></u>

  • <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>

Explanation:

Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.

                       \dfrac{V}{T}=k\\\\V=kT

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.

When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

Meaning that the Volume at 273.15ºC is zero.

You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.

3 0
3 years ago
What was Thomson's model of the atom called?
trasher [3.6K]
The answer is C: The plum-pudding model
3 0
3 years ago
What propertys does the rock state-of -matter have that wont let Logan poke his finger through it?
adell [148]
A rock is a solid, so Logan can't poke his finger through it.
4 0
3 years ago
A scientific ________ must have a control, so that the variables that could affect the out come is reduced. A:experiment B:concl
Lostsunrise [7]

Answer:

A.experiment

Explanation:

hope this helps

4 0
3 years ago
The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi
galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

<u>Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.</u>

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}

So,

Moles of Nitric acid  = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

moles=\frac{Mass\ taken}{Molar\ mass}

Thus,  

Mass\ of\ Nitric\ acid=Moles \times Molar mass}

Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}

<u>Mass of Nitric acid = 116.55 g</u>

Also,

Density=\frac{Mass}{Volume}

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}

Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}

<u>Mass of the solution  = 1640 g</u>

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}

So,

Mass \%=\frac{116.55}{1640} \times {100}

<u>Mass % = 7.1067 %</u>

6 0
3 years ago
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