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zavuch27 [327]
3 years ago
8

A toy car on a string is pulled across a table horizontally. The string is at an

Physics
1 answer:
svlad2 [7]3 years ago
5 0

(C)

...........................

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A 0.16 kg billiard ball moving at 1.20 m/s collides elastically with one of the same mass at rest. It continues at a speed of 0.
Rainbow [258]
Use energy conservation to calculate the speed!
Total kinetic energy before collision = total kinetic energy after the collision.
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How long does it take a person at rest to breathe one mole of air if the person breathes 77.0 ml/s of air that is measured at 25
Natali5045456 [20]
<span>320. seconds The ideal gas law is PV = nRT where P = pressure of the gas V = volume of the gas n = number of moles of the gas R = the ideal gas constant T = absolute temperature of the gas. Since we're going to want the volume, solve for V PV = nRT V = nRT/P 755 mmHg converts to 100658.11 Pascals 25 C = 298.15 K Let's calculate nT/P, then we'll multiply by R 1 mol * 298.15 K / 100658.11 Pa = 0.002962007 K mol/Pa The value for R in the most convenient units is 8.3144598 m^3 Pa/(K mol), so 0.002962007 K mol/Pa * 8.3144598 m^3 Pa/(K mol) = 0.024627486 m^3 So 1 mole of air at the specified temperature and pressure has a volume of 24.627 liters. The rest of the problem is now trivial. Just divide by the rate of consumption, so 24.627 l / 0.0770 l/s = 319.8374798 s Rounding the result to 3 significant figures gives 320. seconds.</span>
4 0
3 years ago
Which factor should change when comparing the boiling times of the liquids?
Andru [333]

Answer: B

Explanation:

7 0
3 years ago
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Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and
mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

\lambda=\frac{v}{f}

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v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

f=288 Hz

v=1.45\cdot 10^3 m/s

Substituting into the equation, we find the wavelength:

\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m

3 0
4 years ago
2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)
Gwar [14]

Answer:

2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)

was at rest at the beginning, what speed did it achieved because of the work done on it? (Hint:

Calculate the works performed by the force first.)

I figured that is 8.2m/S,I am just not sure can anyone help me i much appreciate it.

4 0
3 years ago
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