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2 years ago

15

this is what im talking about people. who ever is doing this is a p.e.d.o file and a pe.rv. you need to get off this site and go

somewhere ells and i don't care where you go but there are kids on here. go the fu ck away.

2 answers:

Anna007 [38]2 years ago

7 0

Literally didn't ask + seethe + mald + counter ratio + don't care + r.i.p bozo gg ez

sergey [27]2 years ago

6 0

Answer:

ewwwwwwww thats nasty

Step-by-step explanation:

You might be interested in

Verify that (a+b)+c = a+ (b+c) by taking a = -8 , b = (-8/11) , c = (-8/12)

gogolik [260]

Answer:

Step-by-step explanation:

$(-8+-\frac{8}{11} ) + (-\frac{8}{12}) = -\frac{96}{11} + (-\frac{2}{3}) = -\frac{288 + 22}{33}) = -\frac{310}{33}\\ (-8) + (-\frac{8}{11} + (-\frac{2}{3})) = (-8) + (-\frac{46}{33})= -\frac{310}{33}$

6 0

3 years ago

Read 2 more answers

What are the zeros of the function below? Check all that apply.

galina1969 [7]

Answer:

x = 3 or x = 2 or x = -1 or x = -5

Step-by-step explanation:

Solve for x:

((x - 3) (x - 2) (x + 1) (x + 5))/x = 0

Multiply both sides by x:

(x - 3) (x - 2) (x + 1) (x + 5) = 0

Split into four equations:

x - 3 = 0 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0

Add 3 to both sides:

x = 3 or x - 2 = 0 or x + 1 = 0 or x + 5 = 0

Add 2 to both sides:

x = 3 or x = 2 or x + 1 = 0 or x + 5 = 0

Subtract 1 from both sides:

x = 3 or x = 2 or x = -1 or x + 5 = 0

Subtract 5 from both sides:

Answer: x = 3 or x = 2 or x = -1 or x = -5

8 0

2 years ago

Read 2 more answers

Kiara spent $36 and had $12 left.<br><br> what percent money did she spend

Illusion [34]

Answer:

she spent 75%

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

3 0

3 years ago

A 650-pund snowmobile trailer is sitting on an exit ramp inclined at 40 degrees

Dima020 [189]

Um what. This doesn’t make sense. Your not even asking a question

6 0

2 years ago