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levacccp [35]
3 years ago
7

What is the difference between a galvanic cell and an electrolytic cell? APEX

Chemistry
1 answer:
Feliz [49]3 years ago
4 0

Answer:

A. A galvanic cell generates electrical current, and an electrolytic cell uses electrical energy to cause redox reactions to occur.

Explanation:

A galvanic cell produces electrical energy through the conversion of chemical energy whereas the electrolytic cell carries out the conversion of the electrical energy/current supplied to it into chemical energy. The reaction that takes place in the galvanic cell is spontaneous which is responsible for the electrical energy that is produced. The redox reaction in the electrolytic cell is not spontaneous. Electrical energy has to be supplied to it in order to initiate the reaction.

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An endothermic solution process is described by which of the following?
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Answer:

a. ΔΗ > 0, solution feels cold

Explanation:

Hello,

In this case, endothermic process are those in which we can find that the products have more energy than the reactants, therefore energy is absorbed, for which the following equation:

\Delta H=\Delta H_{products}-\Delta H_{reactants}

Must be greater than 0 (positive) thereby, for a solution process we find that the solution feels cold, in such a way, answer is a. ΔΗ > 0, solution feels cold.

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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq) , as described b
Nostrana [21]

Answer:

0.676 grams of manganese (IV) oxide should be added.

Explanation:

Moles of chlorine gas = n

Volume of the chlorine gas = V = 205 mL = 0.205 L

Pressure of the chlorine gas = 705 Torr = \frac{705}{760}atm=0.928 atm

1 atm = 760 Torr

Temperature of the chlorine gas = T = 25°C = 25 + 273 K = 298 K

PV=nRT ( ideal gs equation)

n=\frac{PV}{RT}=\frac{0.928 atm\times 0.205 L}{0.0821 atm L/mol K\times 298 K}=0.00777 mol

MnO_2(s)+4HCl(aq)\rightarrow MnCl_2(aq)+2H_2O(l)+Cl_2(g)

According to reaction, 1 mole of chlorine gas is obtained from  1 mole of manganese(IV) oxide,then 0.00777 moles of chlorine gas will be obtained from :

\frac{1}{1}\times 0.00777 mol=0.00777 mol of manganese (IV) oxide

Mass of 0.00777 moles of manganese (IV) oxide:

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0.676 grams of manganese (IV) oxide should be added.

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