12x2-7=6-2x2+2
14x^2-15=0
a=14 , b =0 , c=-15
0^2-4x14x(-15) =
840
Answer:
![y = (x+4)^{2}+6](https://tex.z-dn.net/?f=y%20%3D%20%28x%2B4%29%5E%7B2%7D%2B6)
Step-by-step explanation:
The parabola with vertex at point (h,k) is described by the following model:
![y - k = C\cdot (x-h)^{2}](https://tex.z-dn.net/?f=y%20-%20k%20%3D%20C%5Ccdot%20%28x-h%29%5E%7B2%7D)
The equation which satisfies the conditions described above:
![y - 6 = (x+4)^{2}](https://tex.z-dn.net/?f=y%20-%206%20%3D%20%28x%2B4%29%5E%7B2%7D)
![y = (x+4)^{2}+6](https://tex.z-dn.net/?f=y%20%3D%20%28x%2B4%29%5E%7B2%7D%2B6)
The two points are evaluated herein:
x = -6
![y =(-6+4)^{2}+6](https://tex.z-dn.net/?f=y%20%3D%28-6%2B4%29%5E%7B2%7D%2B6)
![y = (-2)^{2}+6](https://tex.z-dn.net/?f=y%20%3D%20%28-2%29%5E%7B2%7D%2B6)
![y = 4 + 6](https://tex.z-dn.net/?f=y%20%3D%204%20%2B%206)
![y = 10](https://tex.z-dn.net/?f=y%20%3D%2010)
x = -2
![y = (-2+4)^{2}+6](https://tex.z-dn.net/?f=y%20%3D%20%28-2%2B4%29%5E%7B2%7D%2B6)
![y = 2^{2} + 6](https://tex.z-dn.net/?f=y%20%3D%202%5E%7B2%7D%20%2B%206)
![y = 4 + 6](https://tex.z-dn.net/?f=y%20%3D%204%20%2B%206)
![y = 10](https://tex.z-dn.net/?f=y%20%3D%2010)
The equation of the translated function is
.
You should expect 28 defected cars.
The area of a square is its side length squared. So the side length of the square squared is 42, so the side length of the square is sqrt(42). The perimeter of the square is 4 times the side length, or 4sqrt(42), which is approximately 25.92.
Answer:
this look hard what grade
Step-by-step explanation: