For
ax^2+bx+c=
and a=1
b/2 squared=c makes a perfect square
b=16
16/2=8
8^2=64
the value of c should be 64
factored form
(x+8)^2
Step-by-step explanation:
The domain is the possible x values of a function.
Since our function is a reciprocal function, our denominator can't equal 0. Note x=0, is a vertical asymptote.
So our domain is
All Reals except 0,
or (-oo,0) U (0, oo).
I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].
Bone dry, sorry nothing I can do about that
