The answer for this question is c
0.87 is the answer.
Explanation : 0.87molNa x 2mol Hcl /2mol Na = 0.87
The chemical reaction would be as follows:
CO + 2H2 =CH3OH
We are given the amount of reactants to be used. We have to use these amounts to determine which is the limiting reactant and how much of the excess reactant is left.
1.50x10^-6 g CO ( 1 mol / 28.01 g ) = 5.36x10^-8 mol CO
6.80 x10^-6 g H2 ( 1 mol / 2.02 g ) = 3.37x10^-6 mol H2
Therefore, it is CO that is consumed completely in the reaction and the number of moles gas left would be 3.37x10^-6 - 5.36x10^-8 = 3.32x10^-6 moles.
I hope this helps in some way. I forgot to mention that the question states they want to find THE NUMBER OF MOLES for H2O. Yherefore, you would want mol of H2O on top.