IF THE VECTOR COMPONENTS OF VECTOR A ARE MULTIPLIED BY 9 THEN THE MAGNITUDE OF VECTOR A IS INCREASES BY A FACTOR OF .........

If you increase the resistance in a series circuit, ________________

GrogVix [38]

B) the current will decrease

6 0

3 years ago

Guys I need help with my homework please !!!!

Sergio [31]

Answer:

(a) To draw water from a well we have to pull at the rope.

(b) A charged body attracts an uncharged body towards it.

(c) To move a loaded trolley we have to pull it.

(d) The north pole of a magnet repels the north pole of another magnet.

Explanation:

Just trust me

6 0

3 years ago

Prepare a summary to explain how much the final birds varied from the original birds after 1 million years of natural selection.

mezya [45]

Answer:

your father️️️ just 5 points

5 0

3 years ago

How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)

o-na [289]

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

Let the diameter of one drop is 1 cm

so volume of one drop is given by

$V = \frac{1}{6}\pi d^3$

now we have

$V = \frac{1}{6}\pi(0.01)^3$

$V = 0.53 \times 10^{-6} m^3$

now in 1L of liquid let say N drops are there

so we have

$1L = 10^{-3} m^3$

now we have

$N = \frac{10^{-3}}{0.53 \times 10^{-6}}$

$N = 2\times 10^3$

so it will have approx 2000 drops in it with diameter 1 cm each drop

7 0

3 years ago

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A toy gun uses a spring to project a 4.5-g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the gu

marishachu [46]

Answer:

1.93 m/s

Explanation:

Parameters given:

Mass = 4.5g = 0.0045kg

Spring constant = 8.0 N/m

Length of barrel = 13 cm = 0.013m

Frictional force = 0.035N

Compression = 5.8 cm = 0.058m

First, we find the P. E. stored in the spring:

P. E. = ½*k*x²

P. E. = ½ * 8 * 0.058² = 0.013J

Then, we find the work done by the frictional force while the sphere is leaving the barrel of the gun:

Work = Force * distance

The distance here is the length of the barrel.

Work = 0.035 * 0.13 = 0.0046 J

The kinetic energy of the sphere can now be found:

K. E. = P. E. - Work done

K. E. = 0.013 - 0.0046 = 0.0084J

We can now find the speed using the formula for K. E.:

K. E. = ½*m*v²

0.0084 = ½ * 0.0045 * v²

v² = 0.0084/0.00255 = 3.733

=> v = 1.93 m/s

4 0

3 years ago

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