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larisa [96]
2 years ago
12

The information below describes a redox reaction.

Chemistry
1 answer:
klio [65]2 years ago
6 0
The answer is 2 of the coefficient of silver
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What is the molar mass of PbSO4
Sladkaya [172]

Molar Mass=
303.26 g/mol


7 0
4 years ago
Which atom has higher electron affinity F or I, Why?​
pshichka [43]
Down a group, electron affinity typically decreases. This is because the atomic radius increases down a group.
Fluorine, which is higher up the group then chlorine, has a lower electron affinity. This is because the electrons in the outermost shell of a fluorine atom are closer together.
The electron gained also feels a great amount of repulsion from the electrons originally in the outermost shell. Energy is required to keep the gained electron in the shell, causing fluorine to have a smaller electron affinity than chlorine.
Hope this helps :)
8 0
3 years ago
How many grams of silver chloride can be prepared by the reaction of 105.0 ml of 0.22 m silver nitrate with 105.0 ml of 0.13 m c
Ksenya-84 [330]
The balanced equation for the above reaction is as follows;
2AgNO₃ + CaCl₂ ---> 2AgCl + Ca(NO₃)₂
stoichiometry of AgNO₃ to CaCl₂ is 2:1
we first need to find the limiting reactant 
number of moles reacted = molarity x volume
number of AgNO₃ moles = 0.22 mol/L x 0.1050 L = 0.023 mol
number of CaCl₂ moles = 0.13 mol/L x 0.1050 L = 0.014 mol
according to molar ratio of 2:1
if we assume AgNO₃ to be the limiting reactant 
if 2 mol of AgNO₃ react with 1 mol of CaCl₂
then 0.023 mol of AgNO₃ reacts with - 0.023/2 = 0.012 mol of CaCl₂
0.012 mol of CaCl₂ is required but 0.014 mol of CaCl₂ is required
therefore CaCl₂ is in excess and AgNO₃ is therefore the limiting reactant 

the amount of products formed depends on the amount of limiting reactant present 
stoichiometry of AgNO₃ to AgCl is 2:2
the number of moles of AgCl formed = number of AgNO₃ moles reacted 
therefore number of AgCl moles formed = 0.023 mol
mass of AgCl formed = 0.023 mol x 143.3 g/mol = 3.3 g
mass of AgCl formed = 3.3 g
6 0
3 years ago
Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c
nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1

HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2

Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹

so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  

7 0
3 years ago
Read 2 more answers
In the final stage of the nuclear fuel cycle, the spent fuel must be transported, processed, and disposed of properly. True Fals
Aleksandr [31]
True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal. 
8 0
3 years ago
Read 2 more answers
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