Answer:
- <em>Chemical equations are balanced </em><u>to comply with the law of conservation of mass.</u>
Explanation:
Law of conservation of mass states that matter cannot be either created or destroyed.
A skeleton chemical equation shows the reactants and products of a chemical reaction without taking into account the real proportion in which the reactants combine and the products are obtained.
An example of a skeleton reaction is the combustion of methane:
Such as that equation is shown, there are four atoms of hydrogen in the reactants but only 2 atoms of hydrogen in the products. Also, there are 2 atoms of oxygen in the reactants but three atoms of oxygen in the products. This seems to show that some atoms of hydrogen have been destroyed and some atoms of oxygen have been created. This is impossible as it is against the law of conservation of matter.
Then, to show a real situation, the chemical equation of combustion must be balanced, adjusting the coefficients. This is the balanced chemical equation:
Now you see that the number of atoms of each matter is conserved: the number of carbon atoms in each side is 1, the number of atoms of hydrogen in each side is 4, and the number of atoms of oxygen in each side is 4. Thus, by balancing the chemical equation, the law of conservation of mass is not violated.
The volume of the sample after the reaction : V₂=5.484 L
<h3>Further explanation</h3>
Given
Reaction
2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)
0.1100 mol of HBr(g)
5x10⁻² mol of Cl2(g)
Required
The volume of the sample after reaction
Solution
Find limiting reactant :
0.11/2 : 0.05/1 = 0.055 : 0.05
Limiting reactant : Cl₂
mol Products based on mol Cl₂
mol products = mol HCl + mol Br₂
mol products = 2/1x0.05 + 1/1x0.05
mol products = 3 x 0.05 = 0.15
mol reactants = 0.11 + 0.05 = 0.16
<em>From Avogadro's law, </em>
In the same T, P, and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
1 = reactants, 2 = products
Input the value :
5.85/0.16=V₂/0.15
V₂=5.484 L
A concave<span> surface, </span>structure<span>, or line. tr.v. con·caved, concaving, con·caves.
hope that helped</span>
