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Oksana_A [137]
3 years ago
9

To what temperature does a 250.0-ml cylinder containing 0.1000 mol he need to be cooled in order for the pressure to be 253.25 k

pa
Chemistry
2 answers:
Elza [17]3 years ago
7 0
76.19 K according to Gradpoint (my hw). 

Nuetrik [128]3 years ago
3 0

Answer:

T = 76.09 K

Explanation:

<u>Given:</u>

Moles of He, n = 0.1000

Volume, V = 250.0 ml = 0.250 L

Pressure, P = 253.25 kPa

<u>To determine:</u>

Temperature, T

<u>Formula:</u>

Based on the ideal gas law: PV = nRT -----(1)

R = 0.0821 L.atm/mol-K

P = 253.25 kPa

Now, 1 kPa = 0.00987 atm

Therefore, 253.25 kPa = 2.499 atm

Based on equation (1)

T = \frac{PV}{nR} = \frac{2.499 atm*0.250 L}{0.1000 mol *0.0821 Latm/mol-K}=76.09 K

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<u>Answer:</u> C) be hypertonic to Tank B.

<u>Explanation: </u>

<u> The ability of an extracellular solution to move water in or out of a cell by osmosis</u> is known as its tonicity. Additionally, the tonicity of a solution is related to its osmolarity, which is the <u>total concentration of all the solutes in the solution. </u>

Three terms (hypothonic, isotonic and hypertonic) are used <u>to compare the osmolarity of a solution with respect to the osmolarity of the liquid that is found after the membrane</u>.  When we use these terms, we only take into account solutes that can not cross the membrane, which in this case are minerals.

  1. If the liquid in tank A has a lower osmolarity (<u>lower concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypotonic with respect to the latter.
  2. If the liquid in tank A has a greater osmolarity (<u>higher concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypertonic with respect to the latter.
  3. If the liquid in tank A has the same osmolarity (<u>equal concentration of solute</u>) as the liquid in tank B, the liquid in tank A would be isotonic with respect to the latter.

In the case of the problem, option A is impossible because the minerals can not cross the membrane, since it is permeable to water only. There is no way that the concentration of minerals decreases in tank A, so <u>the solution in this tank can not be hypotonic with respect to the one in Tank B. </u>

Equally, both solutions can not be isotonic and neither we can say that the solution in tank A has more minerals that the one in tank B because the liquid present in tank B is purified water that should not have minerals. Therefore, <u>options B and D are also not correct.</u>

Finally, the correct option is C, since in the purification procedure the water is extracted from the solution in tank A to obtain a greater quantity of purified water in tank B. In this way, the solution in Tank A would be hypertonic to Tank B.

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Explanation:

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2) The gas molecules collide with each other and also with wall of container and this collision is elastic.

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