Answer:
E = 2.05×10⁻²³ J
Explanation:
Given data:
Wavelength of transmission = 9.7 mm (9.7/1000 = 0.0097 m)
Energy of transition = ?
Solution:
9.7 mm (9.7/1000 = 0.0097 m)
9.7×10⁻³ m
Formula:
E = hc/λ
By putting values,
E = 6.63 ×10⁻³⁴ Js × 3×10⁸ m/s / 9.7×10⁻³ m
E = 19.89×10⁻²⁶ J.m / 9.7×10⁻³ m
E = 2.05×10⁻²³ J
1.7960L
Explanation:
the mass of the gas is constant in both instances
pv/T=constant(according to pv=nRT)
745mmHg*2L/298K=760mmHg*v/273K
v=1.7960L
Deshielding due to an electronegative element close by is the common reason for observing increased chemical shift of a c-h proton
<h3>
What is a chemical shift? </h3>
The resonance frequency of a proton in relation to a standard compound is represented by chemical shift. Chemical shift, which is measured in ppm and is represented by the sign (δ), (parts per million).The chemical shift in a proton NMR spectrum provides details about the targeted proton's chemical surroundings. The structure of the investigated substance, especially electronegative components or effects, has a significant impact on the chemical shift value. Electronegative elements' ability to remove electron density from the proton, which raises the chemical shift value, is one explanation for this. The proton is more exposed to the magnetic field that is being applied externally as a result of this process, which is referred to as de-shielding.
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During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.
<h3>What is electrolysis?</h3>
Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them. In this process, the atoms and ions are interchanged by the addition or removal of electrons.
The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.
During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.
At anode : 2 Cl⁻ → Cl₂ + 2e⁻
At cathode: 2 Li⁺ + 2e⁻ → Li
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