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The equation of a circle in standard form is
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
Here is your answer! The coefficient of xy is 6. To solve this problem, you need to multiply your two polynomials together. I used the FOIL Method- multiply the First two, the Outside two, the Inside two, and the Last two. You can see how I did it on the picture attached. Next, the answer that you get as a result from FOILing is your polynomial. If you look at the number before xy, that is the coefficient. A coefficient is a number that is right before and attached to a variable. I hope this helps you! :))
