Answer:
4 mol of KOH would produce 116.6 g of Mg(OH)₂
Explanation:
According to the following balanced equation:
- MgCl₂+ 2 KOH -----> Mg(OH)₂ + 2 KCL
One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.
using cross multiplication
2 mol of KOH → 1 mol of Mg(OH)₂.
4 mol of KOH → ?? mol of Mg(OH)₂.
no of moles of Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol
Now we can convert moles of Mg(OH)₂ to grams using the formula
mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g
- So, 4 mol of KOH would produce 116.6 g of Mg(OH)₂.
Combined gas law is
PV/T = K (constant)
P = Pressure
V = Volume
T = Temperature in Kelvin
For two situations, the combined gas law can be applied as,
P₁V₁ / T₁ = P₂V₂ / T₂
P₁ = 3.00 atm P₂ = standard pressure = 1 atm
V₁ = 720.0 mL T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K
By substituting,
3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
V₂ = 2012.6 mL
hence the volume of gas at stp is 2012.6 mL
Answer:
All matter is made up of tiny particles called <em><u>a</u></em><em><u>t</u></em><em><u>o</u></em><em><u>m</u></em><em><u>s</u></em><em><u>.</u></em> Atoms are made up of three subatomic particles known as <em><u>proton</u></em><em><u>,</u></em><em><u> </u></em><em><u>neutron</u></em><u> </u>and<em><u> </u></em><em><u>electron</u></em><em><u>.</u></em> Protons and neutrons are located in the <em><u>nucleus</u></em><em><u>.</u></em>
The nucleus is dense and takes up very little space within the atom. All protons have a <em><u>positive</u></em><em><u> </u></em>charge and have a mass of about 1 amu. All neutrons have no charge or are <em><u>neutral</u></em> and have a mass of about 1 amu.
Electrons are located in the area known as electron cloud. Electrons orbit around the nucleus and have a <em><u>negative</u></em> charge
Answer:
0.00191 meter is the diameter of the sphere.
Explanation:
Velocity of the rigid sphere = 
Density of the fluid = 
Density of the particle= 
Viscosity of the fluid =
Radius of the sphere = r

(Terminal velocity)

r = 0.00191 m
0.00191 meter is the diameter of the sphere.