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grandymaker [24]
2 years ago
5

3g of clean mg ribbon and 8g of clean copper metal was burnt separately in equal volume of air and both mass reacted completely

with air state and explain where they was greater change in mass??​
Chemistry
1 answer:
dsp732 years ago
5 0

Answer:

gshshs

Explanation:

bshsjskskehhshs

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Calculate the total quantity of heat required to convert 25.0 g of liquid ccl4(l from 35.0°c to gaseous ccl4 at 76.8°c (the norm
GREYUIT [131]

The solution would be like this for this specific problem:

<span>25.0 g CCl4 x (1 mole CCl4 / 153.8 g CCl4) = 0.163 moles CCl4 

 </span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ 

total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ 

<span>I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

6 0
3 years ago
As white light passes through a prism, the light is ____<br><br> A. Reflected <br> B. Refracted
noname [10]

Answer:

Refracted

Explanation:

White light refracts when it passes through a prism. Each wavelength refracts at a different angle, and the emergent light forms a rainbow.

3 0
3 years ago
Read 2 more answers
A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di
Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

<em>Initial mass MnO₂ = 0.6467g</em>

<em>Recovered mass = 0.3104g</em>

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

<em>Moles MnO₂ -Molar mass: 86.9368g/mol-:</em>

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

<em>Moles Cl⁻:</em>

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

<em>Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:</em>

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

<em>0.3439g of AlCl₃</em> are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0
2 years ago
How many grams of hydrogen gas get produced if 10 g of aluminum reacts?
Degger [83]

Answer:

9.8

Explanation:

8 0
3 years ago
On a recent car ride, a student traveled the first 20 kilometers in 5 minutes, the next 60 kilometers in 50 minutes, and the las
inn [45]

Answer:

it is 90 km in one hour it is 90km/h

90/60=1,5

6 0
2 years ago
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