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aliina [53]
3 years ago
8

What is the product(s) of the reaction below?

Chemistry
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

A. Solid aluminum oxide and solid iron

Explanation:

The reaction equation is given as:

    2Al  +   Fe₂O₃  →   Al₂O₃   + 2Fe

The species on the left hand side are the reactants

Those on the right hand side of the expression are the products.

The products are:

Al₂O₃   and Fe

 These are solid aluminum oxide and solid iron

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When a radioactive isotope releases an alpha particle, the atomic number of the atom is (2 points)
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When alpha decay takes place, two protons and two neutrons are forcefully ejected from the nucleus in a way that looks very similar to a Helium nucleus. This type of decay causes the atomic mass of the parent particle to drop by four (four particles lost), but the atomic number drops by only two (two protons lost). Therefore, your answer is C.
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3 years ago
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A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )

V_{2} = 0.000151 m^{3}

This is the final volume of the sample of gas.

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3 years ago
ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST
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What one is the answer?​
geniusboy [140]

Answer:

X:{ \tt{ \green{green \: particle \:» \:  }electron}} \\ Y:{ \tt{ \blue{blue \: particle \:»  \: }proton}} \\ Z:{ \tt{ \red{red \: particle \:» \:  }neutron}}

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The DH for the solution process when solid sodium hydroxide dissolves in water is -44.4 kJ/mol. When a 13.9-g sample of NaOH dis
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Answer:

The temperature increases from 23.0 C to 37.0 °C

Explanation:

<u>Step 1:</u> Data given

DH = -44.4 kJ/mol

mass NaOH = 13.9 grams

mass of water = 250.0 grams

Initial temperature = 23°C = 295 K

Final temperature = TO BE DETERMINED

Specific heat = 4.18 J/g*K

<u>Step 2: </u>Calculate change in temperature

13.9 grams/ 40 g/mol * 44.4 kJ/mol = 15429 J

15429 J = (massNaOH + mass water) * 4.18 * ΔT

15429 = 263.9 *4.18 * ΔT

ΔT = 14°C

<u>Step 3:</u> Calculate final temperature

ΔT= 14°C = T2 - 23°C

T2 = 23 +14 = 37 °C

The temperature increases from 23.0 C to 37.0 °C

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