Answer: The freezing point of 3.46 gram of a compound X in 160 gram of benzene is
Explanation:
The relation of density and molar mass is:
where
d = density = 3.27 g/ L
P = pressure of the gas = 773 torr = 1.02 atm (760 torr = 1atm)
M = molar mass of the gas = ?
T = temperature of the gas =
R = gas constant =
The relation of depression in freezing point with molality:
= depression in freezing point =
=
= freezing point constant = 5.1
m = molality =
Thus the freezing point of 3.46 gram of a compound X in 160 gram of benzene is