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olga_2 [115]
3 years ago
11

Given that p = 3, q= 5 and r= 7, work out the value of 2pqr.

Mathematics
2 answers:
Rufina [12.5K]3 years ago
6 0

Answer:

210

Step-by-step explanation:

Substitute the values for their respective variables.

2pqr\\2(3)(5)(7)\\210

mario62 [17]3 years ago
3 0

Answer:

2pqr =2 (3)(5)(7) = 210

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A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

  • PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
  • PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0
3 years ago
Given the function f(x) = - 4x + 2. Find the range using the domain.<br> D:{-1, 2}<br> R:{ , }
Svet_ta [14]

Answer:

R { - 6, 6 }

Step-by-step explanation:

To find the range substitute the values of x from the domain into f(x)

f(- 1) = - 4(- 1) + 2 = 4 + 2 = 6

f(2) = - 4(2) + 2 = - 8 + 2 = - 6

Range { - 6, 6 }

5 0
3 years ago
CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?
sukhopar [10]

Answer:

Step-by-step explanation:

1.

(c+9)^2=64=8^2\\

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

D

2.

8x^2-3=2

8x^2=5

x^2=\frac{5}{8}=\frac{10}{16}

x=±\frac{\sqrt{10}}{4}

so A

3.

x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2  ±3\sqrt{2}

so D

or

8 0
3 years ago
Please please help me and fast
Eduardwww [97]
Its 12. Part a was 2 part b was 3
6×2=12
4×3=12
4 0
3 years ago
What is the value of 324 + 435 + 546 when written in base 7?
Arada [10]
<span>The sum of 324, 435, and 546 is 1305. If this number were to be expressed by the base of 7, we would need to figure out what value of exponent would satisfy the requirement. This can be done by setting up an equation where 7 to the power of x must equal 1305. Using logarithms, one can solve for x and find it to be 3.6866853. Thus the sum of the aforementioned numbers, expressed in by the base of 7, is 7^3.6866853.</span>
6 0
3 years ago
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